Answer:
Explanation:
Use Avogadro’s number to convert formula units of RbNO₃ to moles of RbNO₃.
1 mol RbNO₃ ≡ 6.022 × 10²³ formula units RbNO₃
Moles of RbNO₃ = 2.41 ×1 0²⁴ × = 4.00 mol RbNO₃
There are of RbNO₃ in 2.41 × 10²⁴ formula units.
Answer:
Option C. 4.03 g
Explanation:
Firstly we analyse data.
12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.
Density is the data that indicates grams of solution in volume of solution.
We need to determine, the volume of solution for the concentration
Density = mass / volume
1.05 g/mL = 100 g / volume
Volume = 100 g / 1.05 g/mL → 95.24 mL
Therefore our 12 g of solute are contained in 95.24 mL
Let's finish this by a rule of three.
95.24 mL contain 12 g of sucrose
Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g
Answer:
She needs to know the Mass and acceleration
Transition Metals can have more than one possible charge.