Which is the first stage of mitosis? A.anaphase B.prophase C.metaphase D.telophase
2 answers:
You might be interested in
Given the data, the correct statement is
Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s
<h3>What is acceleration? </h3>This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
- a is the acceleration
- v is the final velocity
- u is the initial velocity
- t is the time
- Initial velocity (u) = 0 m/s
- Final velocity (v) = 15 m/s
- Time (t) = 10 s
- Initial acceleration (a₁) =?
a₁ = (v – u) / t
a₁ = (15 – 0) / 10
a₁ = 1.5 m/s²
<h3>How to determine the final acceleration of Beverly</h3>- Initial velocity (u) = 15 m/s
- Final velocity (v) = 35 m/s
- Time (t) = 50 - 10 = 40 s
- Final acceleration (a₂) =?
a₂ = (v – u) / t
a₂ = (35 – 15) / 40
a₂ = 0.5 m/s²
<h3>How to determine the initial acceleration of Carl</h3>- Initial velocity (u) = 0 m/s
- Final velocity (v) = 10 m/s
- Time (t) = 10 s
- Initial acceleration (a₁) =?
a₁ = (v – u) / t
a₁ = (10 – 0) / 10
a₁ = 1 m/s²
<h3>How to determine the final acceleration of Carl</h3>- Initial velocity (u) = 10 m/s
- Final velocity (v) = 30 m/s
- Time (t) = 50 - 10 = 40 s
- Final acceleration (a₂) =?
a₂ = (v – u) / t
a₂ = (30 – 10) / 40
a₂ = 0.5 m/s²
SUMMARY
- Initial acceleration of Beverly = 1.5 m/s²
- Final acceleration of Beverly = 0.5 m/s²
- Initial acceleration of Carl = 1 m/s²
- Final acceleration of Carl = 0.5 m/s²
From the above calculations, we can see that Beverly's initial acceleration is higher than that of Carl's and their final acceleration is the same.
Therefore, the correct answer to the question is:
Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s
Complete question
See attached photo
Learn more about acceleration:
#SPJ1
The 0.05 moles of required to make 1 L of solution in which the
concentration is 0. 15 M.
Calculation,
The Sodium phosphate dissolves as follows:
→
To make 1. L of solution in which the concentration is 0. 15 M
The morality of = 0.15 M = number of moles / volume in lit
The morality of = 0.15 M = number of moles /1 Lit
number of moles of = 0.15 mole
The mole ratio is 1: 3
It means, the 1 mole of required to form 3 mole of
So, to form 0.15 mole of = 1×0.15 / 3 moles of
required.
Hence, number of moles of required = 0.05 moles.
learn about moles
#SPJ4