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frutty [35]
3 years ago
15

HELP Pre-algebra Not understanding :/

Mathematics
1 answer:
Contact [7]3 years ago
7 0
The answer will end up being c
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Find the area of the parallelogram shown below.<br> 5<br> 4<br> square units
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Length times width and that will get you an answer
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Let a and b be real numbers where ab+0. Which of the following functions could represent the graph below?
8090 [49]

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O f(x) = x(x – b) 3

Step-by-step explanation:

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What’s the equation for g(x)
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Step-by-step explanation:

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Find the ratio of book price to number of pages for each ordered pair. Round your answer to the nearest hundredth. A 3-column ta
Harlamova29_29 [7]

The ratio of book price to number of pages for the ordered pairs a, b , and c are:

  • <em>A = 0.05</em>
  • <em>B = 0.05</em>
  • <em>C = 0.043</em>

The ratio of book price to number of pages can be evaluated for each ordered pairs as follows;

  • For a = 20.00/400 = 0.05

  • For b = 6.25/125 = 0.05

  • For c = 15.0/350 = 0.043

Therefore, ratio of book price to number of pages for the ordered pairs a, b , and c are:

a = 0.05

b = 0.05

c = 0.043

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6 0
2 years ago
Please help!!!!
koban [17]

Answer:

Correct choice is A

Step-by-step explanation:

If a function has an inverse, then there is at most one x-value for each y-value.

The tangent function is periodic with period \pi. Hence, at each value for which f(x)=\tan x is defined, f(x+n\pi )=\tan x for each integer n. Therefore, the function f(x)=\tan x does not have an inverse. Since tangent is not a one-to-one function, the domain must be limited. From examining the graph of the tangent function, we see that in each interval of the form

\left((2k−1)\dfrac{\pi}{2},(2k+1)\dfrac{\pi}{2}\right)

where k is an integer, the tangent function assumes every value in its range. Moreover, in each such interval, each y-value is achieved exactly once. Hence, we can create an invertible function by restricting the domain tangent function to one such interval. Such interval is an interval between two consecutive vertical asymptotes x=(2k−1)\dfrac{\pi}{2} and x=(2k+1)\dfrac{\pi}{2}.

4 0
3 years ago
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