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3 years ago

How many grams of hydrogen in 1.85moles

1 answer:

5 0

2H2(g) + O2(g) → 2H2O(1) 0 260 g 0.2068 0.180 g 2008 When 45.0 g of CH4 reacts with excess O2, the actual yield of CO2 is 118 g. What is the percent yield? CHA(g) + 2O2(g) - CO2(g) + 2H2O(g) 73.6% 67.9% 95.2% 86.4% For the reaction: 2503(g) + 790 kcal - 25(s) + 3O2(g), how many kcal are needed to form 1.5 moles O2(g)? 790 kcal 395 kcal 2370 kcal 411 kcal When 3 moles of Ny are mixed with 5 moles of H2 the limiting reactant is N2(g) + 3H2(g) - 2NH3(g) H2 NH3 ОООО H20 O N₂

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Which of the following is true of mixtures?

SCORPION-xisa [38]

A. a mixture is a combination of two or more substances in which each substance retains its own properties.

4 0

3 years ago

three molecules of oxygen react with four molecules of hydrogen to produce water molecules write a balanced chemical equation

mixer [17]

Answer:

ExpC

→

This is the balanced reaction equation for the combustion of methane.

Explanation:

The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations.

If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction.

To the left of the arrow, we have our reactants.

To the right of the arrow, we have our products.

The quantity of each individual element in the left must equal the quantity of each individual element in the right.

So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction.

→

Our reactants in this equation are

and

Our next step is to break these down into individual atoms.

We have:

1 C atom, 4 H atoms & 2 O atoms.

If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense?

Now we look to the other side of the equation.

Here we see our products are

Again, we break these down into individual atoms again.

We have:

1 C atom, 2 H atom, 3 O atom

6 0

3 years ago

What volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution?

PolarNik [594]

The volume of 0. 250 m sulfuric acid solution would be needed to react completely with 18. 00 ml of 0. 350 m ammonia solution is 0.0504 L.

The balance reaction is 2KOH+ $H_{2} SO_{4}$ = $2H_{2} O+K_{2} SO_{4}$

This shows us that we need 2 moles of KOH for each mole of sulfuric acid.

So, we write mathematically 2*(0.018*0.350)=(V*0.250)

V=(2*0.018*0.350)/0.250=0.0504 L

<h3>Sulfuric acid</h3>

With the chemical formula H2SO4, sulfuric acid, also known as sulphuric acid or oil of vitriol, is a mineral acid made up of the elements hydrogen, oxygen, and sulfur. It is a viscous liquid that is miscible with water and is colorless, odorless, and viscous.

Since pure sulfuric acid has a significant affinity for water vapor, it does not naturally occur on Earth; as a result, it is hygroscopic and rapidly collects water vapor from the atmosphere. Due to its potent dehydrating and oxidizing qualities, concentrated sulfuric acid is extremely corrosive to various materials, including rocks and metals. One significant exception is phosphorus pentoxide, which dehydrates sulfuric acid to sulfur trioxide instead of being dehydrated by sulfuric acid.

Learn more about Sulfuric acid here:

brainly.com/question/1107054

#SPJ4

6 0

2 years ago

What is the total number of moles of oxygen atoms present in one mole of Mg(CIO3)2?

Hitman42 [59]

4) 6!!!!!!!!!!!!!!
Nanananabxnjajakaz

8 0

3 years ago

Read 2 more answers

Using the Rydberg equation, calculate the energy for the following electronic transitions in a hydrogen atom and label each as a

Murljashka [212]

Answer:

-1.94 * 10^-18 J

Since the electron moved from a higher to a lower energy level (n = 3 → n = 1) it is an emission.

Explanation:

From Rydberg equation;

E = -RH(1/n^2final - 1/n^2initial)

For a transition from n = 3 → n = 1

RH = 2.18 * 10^-18 J

E = -(2.18 * 10^-18) (1/1^2 - (1/3^2)

E = -(2.18 * 10^-18) (1-1/9)

E= -(2.18 * 10^-18) (8/9)

E = -1.94 * 10^-18 J

7 0

3 years ago