According to law of definite proportion, for a compound, elements always combine in fixed ratio by mass.
The formula of compound remains the same, let it be a_{x}b_{y} where, a and b are two different elements.
Since, the ratio of mass remains the same , calculate the ratio of masses of element a and b in both cases
\frac{a}{b}=\frac{15}{35}=\frac{10}{y}
rearranging,
y=\frac{10\times 35}{15}=23.3
Thus, mass of b produced will be 23.3 g.
Answer:
Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol
Mass = 138.63 g
Explanation:
The balanced chemical reaction is shown below:-
Firstly the moles of methane gas reacted must be calculate as:-
Given, mass of methane = 50.6 g
Molar mass of methane gas = 16.04 g/mol
The formula for the calculation of moles is:-
Thus, from the reaction stoichiometry,
1 mole of methane produces 1 mole of carbon dioxide
Also,
3.15 mole of methane produces 3.15 mole of carbon dioxide
Moles of 
= 3.15 mole
Molar mass of = 44.01 g/mol
Mass = Moles*Molar mass = 
g = 138.63 g
<span>IF WE TAKE N=1 IT IS CALLED GROUND STATE. THEN THE OTHER FOLLOWING HIGHER STATES ARE CALLED EXCITED STATES. IF THE ELECTRON IN AN ATOM JUMPS FROM A STATE TO A LOWER STATE, IT LOSES ENERGY. FROM THE GIVEN STATEMENT, THE WAY TO FIND THE ENERGY RELEASED IS GIVEN BY THE FORMULA, E(n)=(-13.6 eV)/n^2. FIRST TO FIND E(5)=(-13.6 eV)/(5)^2, WE GET E(5)=-0.544 eV. E(3)=(-13.6 eV)/(3)^2, WE GET E(3)=-1.5111 eV. THEN WE HAVE TO FIND THE ENERGY TRANSITION LEVEL. ON SUBTRACTING WE GET 0.967eV. THIS ENERGY HAS TO BE CONVERTED IN JOULES. SO WE MAKE E=0.967*(1.60*10^(-19)) J/eV, WHICH CORRESPONDS TO 0.15472*10^(-18) J. WE NEED TO FIND TO THE WAVELENGTH. THE CORRESPONDING FORMULA E = hf = hc/λ, λ = hc/E. BY SUBSTITUTING THE KNOWN VALUES, WE GET THE ANSWER TO BE 1285.548 NM.</span>
Mass is measured in kg and weight is measured in pounds.
Answer:
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Explanation:
