All categories

3 years ago

Why do we need to do all our comparisons at the same temperature and pressure?

Chemistry

1 answer:

saw5 [17]3 years ago

7 0

Answer:

it can affect ur research

Explanation:

we need to do this because temperature and pressure can effect our results. In order to get the most accurate results possible we must keep conditions of a substance that we can control the same.

You might be interested in

How many molecules of nitrogen gas are found in 0. 045 L of nitrogen gas at STP?

stepan [7]

Answer:

See below

Explanation:

.045 liter / 22.4 l / mole * 6.022 x 10^23 molecules/mole * 2 atoms/molecule =

( * 2 becuase nitrogen gas is diatomic)

7 0

2 years ago

What is the mass of 8.3 x 10^23 molecules of ibruprofen (C13H1802 )?

katovenus [111]

I need to comment on this sorry

8 0

3 years ago

Gaseous methane (CH4) reacts with gaseous oxygen gas (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O) . If 0

UkoKoshka [18]

Answer: The percent yield of water is 84.72 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For methane:

Given mass of methane= 0.16 g

Molar mass of methane = 16 g/mol

Putting values in equation 1, we get:

$\text{Moles of methane}=\frac{0.16g}{16g/mol}=0.01mol$

For oxygen gas:

Given mass of oxygen gas = 0.25 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{0.25g}{32g/mol}=0.008mol$

The chemical equation for the reaction is

$CH_4+2O_2\rightarrow CO_2+2H_2O$

By Stoichiometry of the reaction:

2 moles of oxygen gas reacts with 1 mole of methane

So, 0.008 moles of oxygen gas will react with = $\frac{1}{2}\times 0.008=0.004mol$ of methane

As, given amount of methane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of oxygen gas produces = 2 moles of water

So, 0.008 moles of oxygen gas will produce = $\frac{2}{2}\times 0.008=0.008moles$ of water

Mass of water= $moles\times {\text{Molar Mass}}=0.008\times 18=0.144g$

To calculate the percentage yield of titanium (IV) chloride, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 0.122

Theoretical yield of water = 0.144 g

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{0.122g}{0.144g}\times 100\\\\\% \text{yield of water}=84.72\%$

Hence, the percent yield of water is 84.72%.

7 0

3 years ago

A rigid cylinder with a movable piston contains a sample of helium gas. The temperature of the gas is held

Varvara68 [4.7K]

<span>Assuming ideal gas, we can label this system to follow the Boyle's Law. This Law can be applied to systems held at constant temperature. The formula used is: PV=k, where k is a constant. From the formula, P and V are inversely proprotional. So, if you graph P vs V, the graph would start from the top, then curves down towards the right. </span>

8 0

3 years ago

Read 2 more answers

The central atom in ________ does not violate the octet rule. the central atom in ________ does not violate the octet rule. sf4

ruslelena [56]

We have to know which do not violet octet rule.

The central atom in SF₄ does not violate the octet rule. the central atom in CF₄ does not violate the octet rule.

As per octet rule, atoms can combine either by transfer of valence electrons from one atom to another or by sharing of valence electrons in order to have an octet in their valence shell.

The central atom S of SF₄ contains 8 electrons in the valence shell. Also, C atom of CF₄ contains 8 electrons in the valence shell.

ICl₄⁻ contains 9 electrons in the outermost shell.

7 0

3 years ago