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There are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated by using the following formula:
molarity = no. of moles / volume
According to this question, a volume of 2300 mL solution is contained in 0.68 M MgSO4. The number of moles is calculated as follows:
no of moles = 0.68M × 2.3
no. of moles = 1.56
Therefore, there are 1.56 moles of solute present in a 2300 mL solution of 0.68M MgSO4.
Learn more about moles at: brainly.com/question/12127540
Answer:
The electron configuration for calcium is: 1s2 2s2 2p6 3s2 3p6 4s2. Since calcium is in the fourth row and the second column of the s-block on the periodic table of elements, its electron configuration ends in 4s2. Every lower orbital is filled, starting with the 1s orbital.
Explanation:hope this helps
Answer:
One mole of O₂ weighs 32 g
Explanation:
