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Akimi4 [234]
3 years ago
7

Question 4 Solve and report to correct number of significant figure 2.375 + 4.5​

Chemistry
1 answer:
DiKsa [7]3 years ago
8 0

Answer:

6.9 (two sig figs)

Explanation:

2.375 + 4.5 = 6.875 = 6.9

When adding or subtracting, sig figs are determined by the least number of digits past the decimal point.

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Each liter of air has a mass of 1.80 grams. How many liters of air are contained in
g100num [7]

Answer:

25kg

Explanation:

3 0
3 years ago
HELP. NO FAKE ANSWERS. I WILL REPORT. I AM CONFUSED AND NEED HELP. FILL IN THE NOT FILLED BOXES POR FAVOR.
SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
           0.150 × 25/1000 = 0.00375 moles
Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
The equation for the reaction is
2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
Concentration (unknown)
The equation for the reaction is 
NaOH + HBr = NaBr + H2O
The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
                 = 0.0075 moles
NaOH concentration will be 
       = 0.0075 moles × 1000/20
       = 0.375 M

7 0
3 years ago
The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14
Elena-2011 [213]

Answer:

Age of the atifact is 4.2\times 10^{2} years

Explanation:

  • For first -order radioactive decay- A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}
  • A_{t} represents activity of radioactive nuclide after t time, A_{0} represents initial activity of radioactive nuclide and t_{\frac{1}{2}} represents half-life
  • Here, A_{t}=19Bq, A_{0}=20Bq and t_{\frac{1}{2}}=5.73\times 10^{3}years

Plug-in all the given values in the above equation-

19=20\times (\frac{1}{2})^{\frac{t}{5.73\times 10^{3}}}

or, t=4.2\times 10^{2}

So, age of the atifact is 4.2\times 10^{2} years

6 0
3 years ago
A physical change is a change to a sample of matter in which -
Readme [11.4K]

Answer:

its FALSE

Explanation:

FAKE   ITS NOT REAL

8 0
3 years ago
A voltaic cell is constructed with two silver-silver chloride electrodes, where the half-reaction is
NemiM [27]
The silver chloride electrode usually functions as a redox electrode where the equilibrium is achieved between silver and its salt (silver chloride).
The half reaction for this electrode is as follow:
<span>AgCl(s)+e−→Ag(s)+Cl−(aq) where:
</span>(s) refers to solid state
(aq) refers to the aqueous state and 
e- is the electron
5 0
3 years ago
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