In alpha decay, alpha particles are ejected from the nucleus. Which equation represents alpha decay?

Chemistry

2 answers:

Paladinen [302]3 years ago

6 0

Answer:

₉₅Am²²⁴ → ₉₃Np²³⁷ + ₂He⁴ is correct on edge

Alexxandr [17]3 years ago

4 0

Answer:

The first equation shows the alpha decay.

₉₅Am²²⁴ → ₉₃Np²³⁷ + ₂He⁴

Explanation:

The americium with atomic wight 224 undergo alpha decay and produce

₉₃Np²³⁷ . The alpha particle emitted is also called helium nuclei. During this decay some gamma radiations also produce as a byproduct.

₉₅Am²²⁴ → ₉₃Np²³⁷ + ₂He⁴

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

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The element with 4 protons in the nucleus in Beryllium.

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Use the provided reduction potentials to calculate ArGº for the following balanced redox reaction: Pb2+(aq) + Cu(s) → Pb(s) + Cu

nydimaria [60]

Answer : The correct option is, +91 kJ/mole

Solution :

The balanced cell reaction will be,

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First we have to calculate the standard electrode potential of the cell.

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