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Bogdan [553]
3 years ago
9

In alpha decay, alpha particles are ejected from the nucleus. Which equation represents alpha decay?

Chemistry
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴ is correct on edge

Alexxandr [17]3 years ago
4 0

Answer:

The first equation shows the alpha decay.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Explanation:

The americium with atomic wight  224 undergo alpha decay and produce

₉₃Np²³⁷ . The alpha particle emitted is also called helium nuclei. During this decay some gamma radiations also produce as a byproduct.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

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What 3 classes of compounds are elecrolytes
zvonat [6]

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

4 0
2 years ago
Consider the reaction: N2(g) 2 O2(g)N2O4(g) Write the equilibrium constant for this reaction in terms of the equilibrium constan
Valentin [98]

Answer : The equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

Explanation :

The given main chemical reaction is:

N_2(g)+2O_2(g)\rightarrow N_2O_4(g);  K

The intermediate reactions are:

(1) N_2O_4(g)\rightarrow 2NO_2(g);  K_a

(2) \frac{1}{2}N_2(g)+O_2(g)\rightarrow NO_2(g);  K_b

We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:

(1) 2NO_2(g)\rightarrow N_2O_4(g);  \frac{1}{K_a}

(2) N_2(g)+2O_2(g)\rightarrow 2NO_2(g);  (K_b)^2

Thus, the equilibrium constant for this reaction will be:

K=\frac{1}{K_a}\times (K_b)^2

K=\frac{(K_b)^2}{K_a}

Thus, the equilibrium constant for this reaction is, K=\frac{(K_b)^2}{K_a}

5 0
2 years ago
Find the % by mass of the solute in 129.54 g C6H1206 in 525 g H20.
belka [17]

Answer:

19.79%

Explanation:

mass % = (mass solute / total mass) * 100

total mass = 129.54 + 525 = 654.54

solute = C6H12O6

(129.54/654.54) = .1979

.1979 * 100 = 19.79%

7 0
3 years ago
How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
3 years ago
Chondroitin sulfate is abundant in the matrix of
3241004551 [841]

The correct answer to this is:

<span>Chondroitin sulfate is abundant in the matrix of <u>“Cartilage”.</u></span>

<span>A 1 unit of Chondroitin sulfate has a chemical formula of C</span>13H21NO15<span>S. It is usually found attached to proteins as part of a proteoglycan and is a vital structure of cartilage by providing much resistance to compression. Due to this, this chemical has found wide use as a dietary supplement for treatment of osteoarthritis.</span>

4 0
3 years ago
Read 2 more answers
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