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Bogdan [553]
3 years ago
9

In alpha decay, alpha particles are ejected from the nucleus. Which equation represents alpha decay?

Chemistry
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴ is correct on edge

Alexxandr [17]3 years ago
4 0

Answer:

The first equation shows the alpha decay.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Explanation:

The americium with atomic wight  224 undergo alpha decay and produce

₉₃Np²³⁷ . The alpha particle emitted is also called helium nuclei. During this decay some gamma radiations also produce as a byproduct.

₉₅Am²²⁴   →    ₉₃Np²³⁷ + ₂He⁴

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

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Ksenya-84 [330]
Actually, it is true

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3 years ago
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Which of the following is the least reactive nonmetal? A. I B. F C. Br D. Cl
tatyana61 [14]

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5 0
3 years ago
When reactants and products are being formed at an equal rate in a chemical reaction, the ____. a. reaction is endergonic b. fre
attashe74 [19]
<h2>The answer is option b "free energy is zero"</h2>

Explanation

  • The reaction that has negative free energy are called exergonic reactions that means the reactants have more free energy than the product formed.
  • The reaction that has positive free energy are called endergonic reactions that means the final state or the products formed have more free energy than the initial state or the reactants.
  • The reaction that has zero free energy occurs when the free energy of both reactants and the products are same hence the rate of formation of products and reactants are equal.
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3 0
3 years ago
You measure 2.34 g of K2Cr2O7 into a volumetric flask. You dilute the K2Cr2O7 with water to a volume of 250 mL. It takes 35.7 mL
natta225 [31]

Answer:

0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution

Explanation:

The reaction of potassium dichromate, K₂Cr₂O₇ with sodium oxalate, Na₂C₂O₄ in the presence of acid H⁺ is:

K₂Cr₂O₇ + 3Na₂C₂O₄ + 14H⁺ → 2Cr³⁺ + 6CO₂ + 7H₂O + 6Na⁺ + 2K⁺

<em>Thus, 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄</em>

Moles of 2.34g of K₂Cr₂O₇ (Molar mass: 294.185g/mol):

2.34g K₂Cr₂O₇ ₓ (1mol / 294.185g) = 7.954x10⁻³ moles K₂Cr₂O₇

In 250mL = 0.250L:

7.954x10⁻³ moles K₂Cr₂O₇ / 0.250L = 0.0318M K₂Cr₂O₇

Moles in 35.7mL = 0.0357L of this solution are:

0.0357L ₓ (0.0318mol / L) = <em>1.136x10⁻³ moles K₂Cr₂O</em>₇ in solution. As 1 mole of K₂Cr₂O₇ reacts with 3 moles of Na₂C₂O₄, to titrate the moles of K₂Cr₂O₇ in solution you need:

1.136x10⁻³ moles K₂Cr₂O₇ × (3 moles Na₂C₂O₄ / 1 mole K₂Cr₂O₇) =

<em>3.408x10⁻³ moles of Na₂C₂O₄</em>

In 17.8mL = 0.0178L:

3.408x10⁻³ moles of Na₂C₂O₄ / 0.0178L =

<h3>0.191M of Na₂C₂O₄ is the concentration of the original Na₂C₂O₄ solution</h3>

<em />

3 0
2 years ago
True or false. it is safe to heat flammable liquids with a bunsen burner as long as it’s done in a fume hood.
Alborosie
I believe the answer is false. It is not safe <span>to heat flammable liquids with a bunsen burner even when it’s done in a fume hood. It is never recommendable to heat liquids that are flammable since it has a very high risk. Hope this answers the question.</span>
4 0
3 years ago
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