Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.
And lets call m to the result of the first experiment.
If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.
If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.
If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.
And so on.
So the total number of combinations C is the sum of all the cases, where we exami
1 outcome for m = 1
+
2 outcomes for m=2
+
.
.
.
+
M outcomes for m = M
C = 1 + 2 + 3 + 4 +...´+M
That would be C....(1 x 10^-1) + (6 x 10^-2) + (9 x 10^-3)
The answer is 0 I hope that helped
Michael smith and Kary B. Mullís
