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3 years ago

13

Pls quickly brainliest to the first to anwser

2 answers:

NikAS [45]3 years ago

5 0

Explanation:

you're supposed to know the formula of acceleration which is velocity of a time then you can solve the question

fiasKO [112]3 years ago

4 0

Answer:

8m/s^2

Explanation:

hope it helps........

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Displacement vector of 4 km north, 2 km south, 5 km north, and 5km south combine to a total displacement of ? A 2 km South b 16

Andrews [41]

It is C. 16 km north.

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4 years ago

Gennadij [26K]

Answer:

3.675 m

Explanation:

$a_{x} =0$ $v_{xo}=100$ $a_{y} =-g$ $v_{yo}=0$

X-direction | Y-direction

$R=x_{o}+ v_{xo} t$ | $y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2$

$75=100t$ | $y=0+0+\frac{1}{2} (9.8)(0.75)$

$\frac{75}{100} =t$ | $y=3.675 m$

$0.75s=t$

Hope it helps

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3 years ago

The energy source used to produce most of the electrical energy in the United States is called what

AlladinOne [14]

Fossil fuels are the largest source of energy in the US.

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4 years ago

Read 2 more answers

A person is standing on a level floor. His head,upper torso,

spin [16.1K]

Answer:

g = 0.98 m

Explanation:

given data:

upper portion weight 438 N and its center of gravity is 1.17 m

upper legs weight 144 N and its center of gravity is 0.835 m

lower leg weight 88 N and its center of gravity is 0.270 m

position of center of gravity of whole body can be determine by using following relation

$g = \frac{\sum ({m_i g_i)}}{\sum m_i}$

where $m_i$ is mass of respective part and $g_i$ is center of gravity

$g = \frac{\sum{ 438\times 1.17 + 144\times 0.835 + 88\times 0.270}}{438+144+88}$

g = 0.98 m

4 0

3 years ago

A 1.20 m wire has a mass of 6.80 g and is under a tension of 120 N. The wire is held rigidly at both ends and set into oscillati

swat32

Answer:

145.52137 m/s

1.4 m

0.7 m

60.6339 Hz

121.2678 Hz

Explanation:

T = Tension = 120 N

$\mu$ = Linear density = $\frac{m}{L}$

m = Mass of wire = 6.8 g

L = Length of wire = 1.2 m

n = Number of loops

Velocity is given by

$v=\sqrt{\frac{T}{\mu}}\\\Rightarrow v=\sqrt{\frac{T}{\frac{m}{L}}}\\\Rightarrow v=\sqrt{\frac{120}{\frac{6.8\times 10^{-3}}{1.2}}}\\\Rightarrow v=145.52137\ m/s$

The speed of waves on the wire is 145.52137 m/s

Wavelength is given by

$\lambda=\frac{2L}{n}\\\Rightarrow \lambda=\frac{2\times 1.2}{1}\\\Rightarrow \lambda=1.4\ m$

The wavelength of the waves that produces one-loop standing waves is 1.4 m

$\lambda=\frac{2L}{n}\\\Rightarrow \lambda=\frac{2\times 1.2}{2}\\\Rightarrow \lambda=0.7\ m$

The wavelength of the waves that produces two-loop standing waves is 0.7 m

Frequency is given by

$f=\frac{nv}{2L}\\\Rightarrow f=\frac{1\times 145.52137}{2\times 1.2}\\\Rightarrow f=60.6339\ Hz$

The frequency of the waves that produces one-loop standing waves is 60.6339 Hz

$f=\frac{nv}{2L}\\\Rightarrow f=\frac{2\times 145.52137}{2\times 1.2}\\\Rightarrow f=121.2678\ Hz$

The frequency of the waves that produces two-loop standing waves is 121.2678 Hz

4 0

3 years ago