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3 years ago

14. Point P has the coordinates (-2,-4). Point P is dilated with a center at the origin and

Mathematics

1 answer:

DedPeter [7]3 years ago

3 0

Answer:

Step-by-step explanation:

The answer is b (1,-1)

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Last year there were 205 ducks living on the pond. This year there are 20% more ducks living on the pond. How many ducks are liv

Rus_ich [418]

Answer:

246

Step-by-step explanation:

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3 years ago

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In two or more complete sentences, describe how you would draw the graph of the solution set for the following inequality. -3m+1

Marat540 [252]

First find the value of m by solving the inequality.

Solving the inequality we get value of m: m>-4

Now, for drawing the graph, a dotted line will be on -4, as values greater than -4 are included in the graph. and all the portion on right side of -4 is included in the graph.

Step-by-step explanation:

We need to draw the graph of the solution set for the following inequality. $-3m+18 < 30$

First we will solve the inequality and find value of m

$-3m+18 < 30$

Adding -18 on both sides

$-3m+18-18 < 30-18\\-3m$

Dividing both sides by -3 and reversing the inequality i.e < is changed into >

$\frac{-3m}{-3}-4$

So, value of m is: m>-4

So. for drawing the graph, a dotted line will be on -4, as values greater than -4 are included in the graph. and all the portion on right side of -4 is included in the graph.

The graph is shown in figure attached.

Keywords: Solving inequalities

Learn more about Solving inequalities at:

#learnwithBrainly

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4 years ago

What is 8. 05 × 10-5 in standard notation? 0. 0000805 0. 00000805 805,000 8,050,000.

krok68 [10]

It’s 0.0000805 (hope this helps!)

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3 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

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3 years ago

a machine can produce 250 items per hour. if the operator of the machine works 40 hours per week, how many times are made by thi

pantera1 [17]

Assuming that the year has 52 weeks in it, (not a leap year) the machine would produce 520,000. You need to multiply the amount of hours worked by how many items the machine makes in an hour. 40x250=10000. Then you need to multiply the amount of items made in a week by 52 (the number of weeks in a year). 10000x52=520000.

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3 years ago

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