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kolbaska11 [484]
3 years ago
13

Choose the pair(s) of integers that can be substituted into the equation ax2 - 6x + c = 0 so that it has two real solutions.

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

The options are not provided, but method is stated below

Answer:

Quadratic equation ax2 - 6x + c = 0

options would be given for a and c

  1. substitute a and c
  2. check for Discriminant
  3.  b^2 - 4ac \geq  0
  4. 36 -4ac \geq 0

These conditions will fetch us the result required among the options.

Note : the \geq sign will give us the result for Two real unequal solutions and two real equal solutions.  If we only need Real unequal solutions we only use > sign instead of \geq

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Answer:

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Step-by-step explanation:

Step 1:  Use FOIL

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Step 2: <em>combine like terms</em>

y^2+ 10y-3y-30

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and thats all :)

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yuradex [85]
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3 years ago
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