Choose the pair(s) of integers that can be substituted into the equation ax2 - 6x + c = 0 so that it has two real solutions.
1 answer:
The options are not provided, but method is stated below
Answer:
Quadratic equation ax2 - 6x + c = 0
options would be given for a and c
- substitute a and c
- check for Discriminant
-
- 36 -4ac
These conditions will fetch us the result required among the options.
Note : the sign will give us the result for Two real unequal solutions and two real equal solutions. If we only need Real unequal solutions we only use > sign instead of
You might be interested in
Answer:
a. Not Divisible
b. Divisible
c. Divisible
d. Divisible
e. Divisible
Step-by-step explanation:
To find the divisibility we need to follow the PEMDAS rule and check if the total value can be divided by the selected numbers without returning a remainder.
Let's begin with a:
by 33
We now then divide the total amount with 33.
= 31,781.5454
We can see that the value has a decimal point indicating that the total value divided by 33 will return a remainder. So it is NOT Divisible by 33.
Now let's continue on with the others.
by 25
We now then divide the total amount with 25.
= 35,192,575,602
The total value did NOT return a decimal point, therefore making the equation true. IS divisible by 25.
Next on we have:
by 7
As we know in the PEMDAS rule, that addition comes first. In this situation we have to read the equation from left to right and solve which ever comes first.
We now then divide the total amount with 7.
= 375
The total value did NOT return a decimal point, therefore making the equation true. IS divisible by 7.
by 11
We now then divide the total amount with 11.
= 12,005
The total value did NOT return a decimal point, therefore making the equation true. IS divisible by 11.
Last but not the least:
by 24
We now then divide the total amount with 24.
= 476,837,158,203,125
The total value did NOT return a decimal point, therefore making the equation true. IS divisible by 24.