2 years ago

How many real solutions does x²+8x+20=0 have?

Mathematics

1 answer:

garri49 [273]2 years ago

7 0

Answer:

No real solutions

Step-by-step explanation:

Use the discriminant formula, D = b² - 4ac

D = b² - 4ac

Plug in b, a, and c:

D = b² - 4ac

D = (8)² - 4(1)(20)

D = 64 - 80

D = -16

Since the discriminant is negative, there are no real solutions

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How many real solutions does x²+8x+20=0 have?​

How many real solutions does x²+8x+20=0 have?