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Varvara68 [4.7K]
3 years ago
8

Drew added yeast and sugar to lukewarm water and placed it in a flask. He

Chemistry
1 answer:
Harrizon [31]3 years ago
6 0
B bubbles indicated a change
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Does pressure decrease when a gas is removed
vovangra [49]

yes

Explanation:

the volume also decrease. as particles are removed from the space the gas is in, there is a decrease in the number of collisions.

4 0
3 years ago
Which scientist proposed the model of an atom as a nucleus surrounded by electrons?
bezimeni [28]

The answer is Ernest Rutherford.

3 0
3 years ago
Read 2 more answers
A stream of methane gas at 25 bar and 100°C flows into a container that contains methane gas initially at 1 bar and 100°C until
Dafna11 [192]

Since Methane is assumed an ideal gas, we need to know its moles in each streams.

Therefore, we can use the ideal gas law to find the mole in the container by:  

P V=nRT         ⇒     n=PV/R T

n=no of moles of the gas = mass/molar mass

Molar mass o f CO2=44g/mol, mass = 44g

P= 25bar = 101000X25Pa=2.5x106Pa

V = 20L = 20dm3 = 0.02m3

T=100C=373K

R=8.314J/mol.K

n1= 2.5x106Pa x 0.02m3 / 8.314J/mol.K x 373K

n1 = 16.1mols

Similarly for stream 2, we have n2 which is

P=1bar = 100000Pa

T= 100C= 373K

V=200L = 0.02m3

n2= 1x105Pa x 0.02m3 / 8.314J/mol.K x 373K

n1 = 0.645mol

So the new stream is an addition of these two streams of methane which has

n3 = n1 + n2 =16.75mols of methane

T=?

V=200L=0.02m3

P = 25Bar = 2.5x106Pa

T= PV/nR

T = 2.5x106Pa x 0.02m3 / 16.75 x 8.314

T=359K

So the final temperature of the gas in the tank is 359K

6 0
3 years ago
Why does alkali elements react vigorously with water?
HACTEHA [7]

Answer:

Explanation:

Because the alkali metal is really willing to give up its electron much more so than Hydrogen.

The redox reaction looks like this

K ===> K+   +    1 e-    The reduction vo is very high which means that the K really does want to give up that electron.

2H+  +2e- ====> H2  The oxidation vo is almost 0 but the Hydrogen is the perfect recipient for the 2 electrons.

5 0
3 years ago
For elements 1–36, there are two exceptions to the filling order as predicted from the periodic table. draw the atomic orbital d
boyakko [2]

Here we have to draw the atomic orbital diagram of the elements present in the range of ¹H to ³⁶Kr having exception and its number of unpaired electrons present in the molecule.

The two exceptional elements are chromium (Cr) and Copper (Cu) the atomic orbital diagrams are-

²⁴Cr = 1s²2s²2p⁶3s²3p⁶3d⁵4s¹.

²⁹Cu = 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹.

The number of unpaired electrons in Cr and Cu are 6 and 1 respectively.

The atomic orbital diagram of the elements in periodic table is governed by the three rules or principles. Those are (i) The Aufbau principle, (ii) The Pauli exclusion principle and (iii) Hund''s rule of maximum multiplicity.

Among it the Aufbau principle explain the energy level of the atomic orbitals 1s < 2s 2p < 3s < 3P < 3d < 4s etc.

The Pauli's principle tells number of maximum electrons can be present in a particular orbital. As per the principle the s, p and d orbital can posses  maximum 2, 6 and 10 electrons.

the Hund's rules explains the extra stability of the half filled and full filled orbitals.

In ²⁴Cr (after ²³V: 1s²2s²2p⁶3s²3p⁶3d³4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁴4s² having four unpaired electron but as the half filled d-orbital (5 electrons) is more stable thus it posses 1s²2s²2p⁶3s²3p⁶3d⁵4s¹ electronic configuration having 6 unpaired electrons.

In ²⁹Cu (after ²⁸Ni: 1s²2s²2p⁶3s²3p⁶3d⁸4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁹4s² having 1 unpaired electron in d orbital, but due to high stability of the fulfilled d orbital (10 electrons) the atomic orbital diagram become 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹ having same number of unpaired electron is s orbital.

The two exceptional atomic orbital diagram of the element in between ¹H to ³⁶Kr is drawn and number of unpaired electrons are calculated.              

6 0
3 years ago
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