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3 years ago

Does pressure decrease when a gas is removed

Chemistry

1 answer:

vovangra [49]3 years ago

4 0

yes

Explanation:

the volume also decrease. as particles are removed from the space the gas is in, there is a decrease in the number of collisions.

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Why there is not reaction in nac2h3o2(aq)+pb(no3)2(aq)→?

BARSIC [14]

NaC2H3O2 is called sodium acetate (CH3COONa)

2CH3COONa(aq) + Pb(NO3)2(aq) -> 2NaNO3(aq) + (CH3COO)2Pb (aq)

The reaction will not occur because no products will be precipitated, like one of the reactants is in solid form

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3 years ago

Calculate the percent ionization of a 0.447 M solution of nitrous acid

Rudiy27

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3 years ago

What is the molarity of an hno3 solution if 51.0 ml is needed to react with 25.0 ml of 0.150 mkoh solution? the equation is hno3

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3 years ago

Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium

pav-90 [236]

Answer:

The equilibrium concentration of NO is 0.02124 M.

Explanation:

Given that,

Initial concentration of NOBr = 0.878 M

$k_{c}=3.07\times10^{-4}$

Temperature = 24°C

We know that,

The balance equation is

$2NOBr\Rightarrow 2NO+Br_{2}$

Initial concentration is,

$0.878\Rightarrow 0+0$

Concentration is,

$-2x\Rightarrow 2x+x$

Equilibrium concentration

$0.878-2x\Rightarrow 2x+x$

We need to calculate the value of x

Using formula of concentration

$k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}$

Put the value into the formula

$3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}$

$2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}$

$2x^2=0.0002367+0.001228x^2-0.0010536x$

$2x^2-0.001228x^2+0.0010536x-0.0002367=0$

$1.998772x^2+0.0010536x-0.0002367=0$

$x=0, 0.01062$

We need to calculate the equilibrium concentration of NO

Using formula of concentration of NO

$concentration\ of\ NO=2x$

Put the value of x

$concentration\ of\ NO=2\times0.01062$

$concentration\ of\ NO=0.02124$

Hence, The equilibrium concentration of NO is 0.02124 M.

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