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Korolek [52]
2 years ago
8

Label the layers of the earth

Chemistry
1 answer:
Annette [7]2 years ago
8 0
A) crust
b) mantle
c) outer core
d) inner core

hope this helps :)
You might be interested in
During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2
ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass  of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol =<u> 12.81 grams</u>

Step 6:  Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = <u>75.70 grams CO2</u>

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = <u>34.29 grams</u>

3 0
3 years ago
What is mass in science?
Musya8 [376]
Its like weight but not. mass is the amount of matter in a substance.
6 0
3 years ago
Read 2 more answers
A 10 gram iron nail absorbed 125J of heat. What was the final temperature of the nail if the original temperature was 25°C?
valentina_108 [34]

Answer:

52.1 degrees C

Explanation:

We need to use the equation: q = mCΔT, where m is the mass in grams, C is the specific heat capacity, and ΔT is the change in temperature.

Here, m = 10 g and q = 125 J. The heat capacity of iron is about 0.461 J/(g * C). And, our initial temperature is 25. So:

125 J = (10 g) * (0.461 J/(g * C)) * (T_f - 25)

Solving for T_f (final temp), we get: 52.1 degrees C

Hope this helps!

7 0
3 years ago
How many grams of Fe are produced from 65.9 g of FeO given the following reaction: 3FeO + 2Al -&gt; 3Fe +Al2O3
patriot [66]

Using the mole ratio and stoichiomrtery, you get:

65.9 g FeO x (molar mass of FeO) x (3 mol Fe/ 3 mol FeO) x (molar mass of Fe).

Plug in the values and you’re good to go!

8 0
3 years ago
Read 2 more answers
If metal ions in a solution were reduced, what would you expect to see?
Eduardwww [97]

Answer:

The metals that would be able to reduce copper ions in solution would be hydrogen, lead, tin, nickel, iron, zinc, aluminum, magnesium, sodium, calcium, potassium, silver, gold, copper and lithium 5.

Explanation:

7 0
3 years ago
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