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galina1969 [7]
2 years ago
15

Help AsAp i dont get It :(

Mathematics
2 answers:
lutik1710 [3]2 years ago
6 0

Answer:

(0.0)

(1,2.75)

A line that goes through the origin represents a proportional relationship.  Since the line passes through zero-zero, it means that the relationship between the number of notebooks and the cost is proportional The unit rate is represented by the point one-y. The point one, two and seventy-five hundredths represents the unit rate, which means each notebook costs two dollars and seventy-five cents.

Step-by-step explanation Hi angry pomerian

djyliett [7]2 years ago
4 0

Answer:

(0.0)

(1,2.75)

A line that goes through the origin represents a proportional relationship.  Since the line passes through zero-zero, it means that the relationship between the number of notebooks and the cost is proportional The unit rate is represented by the point one-y. The point one, two and seventy-five hundredths represents the unit rate, which means each notebook costs two dollars and seventy-five cents.

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55 balloon gave away every day for 30 days and still have 245 how many did I started with
Debora [2.8K]
To solve for this, we need to multiply 55 balloons by 30 days to get the average total, and then the remainder.
(55 x 30) + 245 = 1895 total balloons to begin with.
3 0
2 years ago
X ( y - x y ), where x= -5 and y= -2
adell [148]

Answer:

60

Step-by-step explanation:

-5(-2-10)

according to pemdas...solve parenthesis first

-5(-12)

= 60

7 0
3 years ago
Read 2 more answers
What are the prime factorizations for 37, 144, 147, and 205?
8_murik_8 [283]
37: 37
144: 2 x 2 x 2 x 2 x 3 x 3
147: 3 x 7 x 7
205: 5 x 41
8 0
2 years ago
In circle P with m NRQ = 37, <br> find the m NPQ.
Anettt [7]

Answer:

53 degrees

Step-by-step explanation:

m<NPQ = 53 degrees

NPQ = 180 - 90 - 37

NPQ = 53 degrees

Hope it helps you love

;)

8 0
2 years ago
Trayectoria de un balón. El siguiente grafico ilustra la trayectoria d en balón de fútbol. La altitud máxima de recorrido del ba
jonny [76]

Answer:

C) Ascenso 6,34 m; Descenso 17,66 m

Step-by-step explanation:

La altitud máxima que recorre la pelota con respecto al suelo, h = 9 metros

La forma general de la ecuación de una parábola es y = a·x² + b·x + c

La velocidad vertical inicial de la pelota, u_y = √(2·g·h)

∴ u_y = √(2 × 9.81 × 9) ≈ 13.288

La velocidad vertical inicial de la pelota, u_y ≈ 13.288 m/s

El tiempo de vuelo de la pelota = 2 × u_y/g ≈ 2 × 13.288/9.81 = 2.709

El tiempo que tarda el balón en alcanzar los 7 metros sobre el suelo se indica de la siguiente manera;

s = u_y·t + (1/2)·g·t²

∴ 7 ≈ 13.288·t - (1/2)×9.81×t²

13.288·t - (1/2)×9.81×t² - 7 ≈ 0

Factorizar con el uso de una calculadora gráfica da;

t ≈ 0.716 s, or t ≈1.993t

Dado que la velocidad horizontal es constante, verificamos entre las opciones dadas una que proporcione los valores de la velocidad horizontal, vₓ, tanto para el ascenso como para el descenso, es decir, para ambos valores de 't' de la siguiente manera;

De las opciones de respuesta dadas, la velocidad horizontal es aproximadamente constante para la única opción 'C', donde tenemos;

vₓ = 6.34/0.716  ≈ 8.85

vₓ = 17.66/1.993 ≈ 8.86

El rango horizontal, d = 8.85 × 2.709 ≈ 24

La distancia horizontal de la pelota durante el ascenso cuando la pelota alcanza una altura de 7 m = 6.34 m, durante el descenso, la distancia horizontal = 17.66 m

La ecuación de una parábola (la trayectoria de la pelota) se puede presentar de la siguiente manera;

y = a·(x - h)² + k

Dónde;

(h, k) = La coordenada del vértice

k = 9

En el origen, (x, y) = (0, 0)

Por lo tanto;

0 = a · (0 - h) ² + 9

a · h² = -9

En y = 7. x = 6.34

∴ 7 = a · (6.34 - h) ² + 9

a = -2 / ((6,34 - h) ²)

a = -2 / ((17,66 - h) ²)

(6,34 - h) ² = (17,66 - h) ²

h²-12,68 · h + 40,1956 = h² -35,32 · h +311,8756

h² -35,32 · h + 311,8756 - (h²-12,68 · h + 40,1956) = 0

-35,32 · h + 12,68 · h = 40,1956 - 311,8756

h = (40,1956 - 311,8756) / (- 35,32 + 12,68)

a = -2 / ((6,34 - 12) ²) ≈ -0,06243054601

La trayectoria de la pelota es y = -0.06243054601 · (x - 12) ² + 9

Por tanto, la mejor opción correcta que cumpla con los parámetros dados es la opción C) Ascenso 6,34 m; Descendencia 17.66 m.

7 0
3 years ago
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