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san4es73 [151]
4 years ago
11

A 50g marble is moving at 2m/s when it strikes a 20g marble at rest. Immediately after the collision, the 50g ball is moving at

1m/s. Is this an elastic collision
Physics
1 answer:
Alika [10]4 years ago
8 0

Answer:

Since the two marbles have different velocities after collision, it can be concluded that the collision is elastic.

Explanation:

Given;

mass of first marble, m₁ = 50g = 0.05 kg

initial velocity of the first marble, u₁ = 2 m/s

mass of second marble, m₂ = 20 g = 0.02 kg

initial velocity of the second marble, u₂ = 0

final velocity of the first marble, v₁ = 1 m/s

Let the final velocity of the second marble, = v₂

Determine the final velocity of the second marble by applying principle of momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

0.05 x 2 + 0.02 x 0 = 0.05 x 1 + 0.02v₂

0.1 = 0.05 + 0.02v₂

0.02v₂ = 0.1 - 0.05

0.02v₂ = 0.05

v₂ = 0.05 / 0.02

v₂ = 2.5 m/s

During inelastic collision both objects will move at the same velocity after collision.

During elastic collision both objects will move at different velocities after collision.

Since the two marbles have different velocities after collision, it can be concluded that the collision is elastic.

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Answer:

a) 37.8 W

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Explanation:

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We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

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We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

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Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

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T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm

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3 years ago
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Answer:

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Explanation:

In the exercise they give the expression for maximum viewing distance

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Ask for this distance for a height of 1100 feet

Let's calculate

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. Let us say that you put a cup of cold water in one room and a cup of hot water in
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Explanation:

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Answer:

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