Answer:
C. 125
Step-by-step explanation:
Given:
Bacteria on day 1 = 5
On day 2, each bacteria got split into 5.
So, number of bacteria on day 2 = 
Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.
So, number of of bacteria on day 3 = 
Therefore, the population of bacteria on day 3 is 125.
Answer:
86.16
Step-by-step explanation:
27+3÷ 3 +4-1+72.4-34.24+6-4+75÷5
PEMDAS
Multiply and divide first
3/3 is 1 and 75/5 = 15
Replace these into the equation
27+1 +4-1+72.4-34.24+6-4+15
Then add and subtract from left to right
31 +72.4-34.24+6-4+15
69.16+6-4+15
86.16
Answer:
√8 ==> 2 units, 2 units
√7 ==> √5 units, √2 units
√5 ==> 1 unit, 2 units
3 ==> >2 units, √5 units
Step-by-step explanation:
To determine which pair of legs that matches a hypotenuse length to create a right triangle, recall the Pythagorean theorem, which holds that, for a right angle triangle, the square of the hypotenuse (c²) = the sum of the square of each leg length (a² + b²)
Using c² = a² + b², let's find the hypotenuse length for each given pairs of leg.
=>√5 units, √2 units
c² = (√5)² + (√2)²
c² = 5 + 2 = 7
c = √7
The hypothenuse length that matches √5 units, √2 units is √7
=>√3 units, 4 units
c² = (√3)² + (4)²
c² = 3 + 16 = 19
c = √19
This given pair of legs doesn't match any given hypotenuse length
=>2 units, √5 units
c² = (2)² + (√5)²
c² = 4 + 5 = 9
c = √9 = 3
legs 2 units, and √5 units matche hypotenuse length of 3
=>2 units, 2 units
c² = 2² + 2² = 4 + 4
c² = 8
c = √8
Legs 2 units, and 2 units matche hypotenuse length of √8
=> 1 unit, 2 units
c² = 1² + 2² = 1 + 4
c² = 5
c = √5
Leg lengths, 1 unit and 2 units match the hypotenuse length, √5
2x^2+(6-1)x-3
2x^2+6x-x-3
2x(x+3)-1(x+3)
(2x-1)(x-1)
Answer:
8^2 ft^2
Step-by-step explanation:
8^2= 64, and to find area it lengthxwidth.
so 8x8=64
