The answer is oxidation.
That is in the redox fueling reaction,
succinate + NAD ↔fumarate + NADPH, the succinate molecule is undergoing oxidation.
As succinate molecule is providing electrons to NAD, so that it can be reduced from NAD to NADPH. So it is losing electrons and undergoing oxidation.
So the answer is oxidation.
Answer: 1.09 g
Explanation:
If we use the approximation that 1 mole is 22.4 L, then setting up a proportion,
- 1/22.4 = x/0.345 (x is the number of moles in the sample)
- x = 0.0154 mol
Since the mass of a mole of chlroine is about 70.9 g/mol, (0.0154)(70.9) = 1.09 g (to 3 s.f.)
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