True, cracking distillation is one process used to break hydrocarbons into smaller and more useful parts. This is achieved by using high temperatures and pressures with a catalyst. The most common catalyst used are the zeolites.
Answer : The ratio of the protonated to the deprotonated form of the acid is, 100
Explanation : Given,

pH = 6.0
To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
Now put all the given values in this expression, we get:
![6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}](https://tex.z-dn.net/?f=6.0%3D8.0%2B%5Clog%20%5Cfrac%7B%5BDeprotonated%5D%7D%7B%5BProtonated%5D%7D)
As per question, the ratio of the protonated to the deprotonated form of the acid will be:
Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100
Answer:
See explanation
Explanation:
The third element in the first transition series is Vanadium
The fourth element in the first transition series is chromium
Given that we have four d orbitals in universe L instead of five as we have on earth;
The electronic configuration of Vanadium in universe L is;
Ar 3d3 4s2
The electronic configuration of chromium in universe L is;
[Ar] 3d4 4s2
Answer:
Some (most) has two tails.You can see the tails when the comets go near the sun.There are two types of comet tails,dust and gas ion. Comet tails can be over 600,000 miles (1 million km) long.Because the comet dust particles are so small, they are pushed away from the Sun into a long tail.They are made of ices, such as water, carbon dioxide, ammonia and methane, mixed with dust.There are so much more to discover about comets (which I might not know).
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744 atomic mass units (a.m.u)
Explanation:
We know that 1 carbon atoms weighs 12 atomic mass units (a.m.u). Knowing this we devise the following reasoning:
if 1 carbon atom have a mass of 12 atomic mass units (a.m.u)
then 62 carbon atoms have a mass of X atomic mass units (a.m.u)
X = (62 × 12) / 1 = 744 atomic mass units (a.m.u)
Learn more about:
atomic mass units
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