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Svet_ta [14]
3 years ago
11

What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =342g/mol, S = 32]​

Chemistry
1 answer:
valentinak56 [21]3 years ago
4 0

Answer: The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

Explanation:

Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.

{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%

Given: mass of sulphur = 32 g/mol

mass of Al_2(SO_4)_3 = 342 g/mol

Putting in the values we get:

{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%

The percentage by mass of sulphur in Al_2(SO_4)_3 is 9.36%

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91 grams of sodium azide required to decompose and produce 2.104 moles of nitrogen.

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