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3 years ago

Lone pair in molecule exert greater solid angle than bond pair. explain?

Chemistry

1 answer:

Sphinxa [80]3 years ago

4 0

Explanation:

The valence shell electron pair repulsion model is best used to explain why lone pair in molecules exert greater solid angle than bond pair.

The VSEPR model determines the total number of electron pairs surrounding the central atom of the species.

Total electron pair = Bond pair + Lone pair

All the electron pairs (like charges) will orient themselves in such a way so as to minimize the electrostatic repulsion between them round an atom.
There are three types of repulsion which are bond pair - bond pair, bond pair - lone pair and lone pair - lone pair.
The repulsion determines the geometry of the covalent bonds around the central atom.
As the number of lone pairs increases, the bond angle diminishes.

learn more:

Lewis structure brainly.com/question/6215269

#learnwithBrainly

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riadik2000 [5.3K]

Answer:

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Explanation:

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3 years ago

How many moles of sucrose are in 5.25x1029 sucrose molecules? (in scientific notation)

Lorico [155]

Answer:

8.72 × 10^5 moles

Explanation:

To find the number of moles in 5.25 x 10^29 molecules of sucrose, we divide the number of molecules by Avagadro constant (6.02 × 10²³ molecules). That is;

no. of moles = no. of molecules ÷ 6.02 × 10²³ molecules

In this case of sucrose, no of moles contained is as follows;

5.25 × 10^29 ÷ 6.02 × 10²³

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0.872 × 10^6

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3 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

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3 years ago

The central core of an atom is called the __?

PilotLPTM [1.2K]

Answer: Atomic Nucleus!

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3 years ago

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liubo4ka [24]

Answer:

Explanation:

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3 years ago