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diamong [38]
3 years ago
11

Andre says that x is 7 because he can move the two 1s with the x to the other side.

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

The image necessary to answer this question is below in the attachment.

Answer: No.

Step-by-step explanation: For this hanger to be in equilibrium, both sides have to equal.

The diagram can be represented as

x + 1 + 1 = 1 + 1 + 1 + 1 + 1

x + 2 = 5

x = 3

So, for this hanger to work, x = 3.

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Answer:

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Step-by-step explanation:

<em>r's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>finding</em><em> </em><em>midpoint</em><em> </em><em>=</em><em>.</em><em>(</em><em> </em><em>X1</em><em> </em><em>+</em><em> </em><em>X</em><em>2/</em><em>)</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>(</em><em>Y1+</em><em>Y2)</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>putting</em><em> </em><em>the </em><em>value</em><em> </em><em>of </em><em>in </em><em>formula</em>

<em> </em><em> </em><em>=</em><em>></em><em> </em><em>x=</em><em> </em><em> </em><em>4</em><em>+</em><em>1</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>1</em><em>-</em><em>6</em><em>/</em><em>2</em>

<em>=</em><em>></em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>/</em><em>2</em><em> </em><em>,</em><em> </em><em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em>/</em><em>2</em>

<em>hope</em><em> it</em><em> helps</em>

3 0
3 years ago
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