Can some PLEASE help me with these inscribed angle questions?

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

3 0

Sure but where are the questions?

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The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

gladu [14]

We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub

p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
$p= \frac {(x-6)(x+1)(x+4)}{(x-2)}$

7 0

3 years ago

The eighth grade math teachers decided to

Lubov Fominskaja [6]

Answer:

this would be your answer not sure if you need to round 4.085 so pretty much the answer would be 3 because you have enough for about 4 and a half

Step-by-step explanation:

4 0

3 years ago

Question 2 What is the quotient? 5,984 = 33 = ?

Serggg [28]

Step-by-step explanation:

$\frac{5984}{33}$

$\frac{5984}{3 \times 11}$

$\frac{544}{3}$

= 181.33

7 0

3 years ago

What is 26.5 rounded to the nearest hundredth??

blagie [28]

Remember your Number system
After the decimal point to the right, the next digit is the TENTH, and next is HUNDREDTH.

So for 26.5 = 26.500.
The tenth digit is 5, and the Hundredth is 0.
After the hundredth digit which is 0, the next digit is also 0.
The second 0 is not up to 5, so we would not add to the first zero.
(Was it 5, or above, we would have added 1 to first zero)

So the answer is 26.50. If the next digit after the hundredth digit was 5 or more the answer would have been 26.51.

But for this question the answer is 26.50 to the nearest hundredth. Cheers.

8 0

3 years ago

Factor completely. x2 + 5x + 6 A. (x - 3)(x + 3) B. (x - 1)(x + 6) C. (x + 3)(x + 2) D. (x + 5)(x + 1)

zhuklara [117]

being $x^{2} +5x+6$ the answer is (x-3)(x-2)

begin $x^{2} -5x+6$ the answer is (x+3)(x+2)

1. $x^{2} +5x+6$

second grade formala is used

$x= \frac{-b±\sqrt{b^{2} } -4ac}{2a}\\ x=\frac{-5±\sqrt{5^{2} } -4.1.6}{2} \\ x= \frac{-5±1}{2} \\ x_{1} =-3 \\ x_{2} =-2$

4 0

3 years ago