Answer:
6
Step-by-step explanation:
I believe 24 because that is the makimum and the biggest box
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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5a)
2x + 94 = 7x + 49 (vertical angles are equal)
2x - 7x = -94 + 49
-5x = -45
x = 9
Answer
9
5b)
4y + 7x + 49 = 180 (supplementary angles, sum = 180)
4y + 7(9) + 49 = 180
4y + 112 = 180
4y = 68
y = 17
Answer
17
6)
x = 6x - 290 (vertical angles are equal)
-5x = -290
x = 58
Answer
58
