Please help me with this question thank you

Here's how you simplify those. The rule for raising an exponent to an exponent is that you multiply them. The rule for dividing exponents with the same base is that you subtract the denomonator from the numerator. So let's simplify the first one, which is actually the most confusing.
$( \frac{ p^{5} }{ p^{-3} q^{-4} } )^{ \frac{1}{4} }$
Multiplying the exponents you get:
$( \frac{ p^{ \frac{5}{4} } }{ p^{- \frac{3}{4} } q^{-1} })$
Subtracting the denominator from the numerator between the common base of p you get this:
$\frac{ p^{ \frac{5}{4}- (-\frac{3}{4}) } }{ q^{-1} }$
Doing that math gives you
$\frac{ p^{2} }{ \frac{1}{q} }$ which equals $\frac{ p^{2} }{1} * \frac{q}{1}$ which is $p^{2}q$ , or the third one down.

The next one:
$( \frac{ p^{2} q^{7} }{ q^{4} } )^{ \frac{1}{2} }$
simplifies to:
$\frac{p* q^{ \frac{7}{2} } }{ q^{2} }$
and subtracting the power of the denominator from the power of the numerator gives you:
$p q^{ \frac{3}{2} }$ , which is the last choice.
$( p^{6}q \frac{3}{2})^{ \frac{1}{3} }$
simplifies to:
$( p^{6* \frac{1}{3} } )( q^{ \frac{3}{2}* \frac{1}{3} })$
which simplifies very nicely to:
$p^{2}q^{ \frac{1}{2} }$ , which is the first choice. The other one is found by process of elimination!

8 0

4 years ago

Help me please!

labwork [276]

Let me see if I can work this out real quick

3 0

3 years ago

There are 19 animals on the farm which contains hens and goats. There are 68 legs in total. How many goats are there on the farm

Masteriza [31]

Answer: 15 goats

Step-by-step explanation:

h = hens - they have 2 legs

g = goats - they have 4 legs

The equations would be:

h + g = 19

2h + 4g = 68

To solve this, I personally prefer substitution, we're isolating h since we need to find g:

h + g = 19

h = 19 - g

Now that we have h, we can plug this into the second equation:

2h + 4g = 68

2(19 - g) + 4g = 68

38 - 2g + 4g = 68

2g = 30

g = 15

There are 15 goats.

Adding onto this, 19 - 15 = 4, so there are 4 hens.

8 0

3 years ago

The answer and how you get it

OLEGan [10]

Answer:

hgcghjgcjhvh

Step-by-step explanation:

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8 0

3 years ago

Use the diagram on the right. How many planes contain both the line and the point

Aloiza [94]

Part (a)

<h3>Answer: 0</h3>

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Explanation:

Point P is part of 3 planes or faces of this triangular prism:

plane PEF (the front slanted plane)
plane PEH (the left triangular face)
plane PHG (the back rectangular wall)

Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.

Each of the three planes mentioned do not involve line FG

Plane PEF only deals with point F
Plane PEH doesn't have any of F or G involved
plane PHG only involves G

So there are no planes that contain line FG and point P.

==================================================

Part (b)

<h3>Answer: 0</h3>

-------------------

Explanation:

It's the same idea as part (a) earlier. The planes involving point G are

plane GQF (triangular face on the right)
plane GFE (bottom rectangular floor)
plane GHP (back rectangular wall)

None of these planes have line EP going through them.

As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are

plane PEH (triangular face on the left)
plane PEF (front slanted rectangular face)

None of these planes have point G located in them.

8 0

3 years ago