The population of the town in 1960 is 48.80 thousands
<h3>How to determine the population in 1950?</h3>
The equation of the model is given as:
f(t) = 42e^(0.015t)
1960 is 10 years after 1950.
This means that:
t = 10
Substitute t = 10 in f(t) = 42e^(0.015t)
f(10) = 42e^(0.015 * 10)
Evaluate
f(10) = 48.80
Hence, the population of the town in 1960 is 48.80 thousands
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Answer:£0.37
Step-by-step explanation:
£4.44/12=£0.37
PLS HELP ASAP I DONT HAVE TIME FOR THIS, IT ALSO DETECTS IF ITS RIGHT IR WRONG PLS HELP ASAP I DONT HAVE TIME FOR THIS, IT ALSO DETECTS IF ITS RIGHT IR WRONG
The value of the function at x = -1 is 5
<h3>What is function?</h3>
Function can be defined as an expression, rule, or law that defines a relationship between one variable known as the independent variable and another called the dependent variable.
From the information given, we have that;
f (x) = 3 (2)x with x=-1
Now, let's substitute the value of x as - 1 in the function given;
f (x) = 3 (2)x
f (x) = 3 (2) -1
Expand the bracket;
f (x) = 6 - 1
f(x) = 5
Thus, the value of the function at x = -1 is 5
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Slope-intercept form:
y=1/3x+11/3
