There are 52 weeks in a year. 1 frog per week: 52 * 1 = 52
So, cloning about 1 frog per week would be reasonable.
Answer:
i
Step-by-step explanation:
i=√-1
Answer:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
Step-by-step explanation:
For this problem we can work with the concentration of water and orange juice.
Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content
Using the concentration of orange juice we have:
(1)
And for the water we have:
(2)
If we solve for X from equation (1) we got:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
Answer:
(-3,1) dhdjdjdjdjejdhdjehehdhdjddjdjddh
(-3,1)
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27