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sattari [20]
3 years ago
11

PLS HELP 50 POINTS!!! function or no function? Pls don't spam I really need help.

Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0

Answer:

function

Step-by-step explanation:

Makovka662 [10]3 years ago
5 0

Answer:

1. function 2. not function

Step-by-step explanation:

You might be interested in
An online furniture store sells chairs for $50 each and tables for $550 each. Every day, the store can ship a maximum of 32 piec
Hunter-Best [27]

Answer:

you have to sell 6 tables to meet all requirements

Step-by-step explanation:

chairs=$50x

tables=$550x

24 chairs×50= $1200

4100-1200= $2900

take $2900 and divide by $550 to find the exact number of tables which is 5 but selling 5 tables and 24 chairs doesnt reach the $4100 mark so I rounded up to 6 tables which doesnt surpass the maximum number of furniture(32) but beats the $4100 mark

3 0
3 years ago
MATH HELP PLZ!!!
RoseWind [281]

Answer:

a)    tan (157.5) = \frac{1-cos 315}{sin315}

b)

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c)

      sin^{2} (157.5) = \frac{1-cos (315) }{2}

d)

  cos 330° = 1- 2 sin² (165°)

       

         

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝  = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ =  2 cos² ∝/2

cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}

b)

cos2∝  = 1- 2 sin² ∝

cos∝  = 1- 2 sin² ∝/2

sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

<u><em>Step(i):-</em></u>

Given

              tan\alpha = \frac{sin\alpha }{cos\alpha }

          we know that trigonometry formulas

        sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

         1- cos∝ =  2 sin² ∝/2

      Given

         tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }

put ∝ = 315

      tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }

     multiply with ' 2 sin (∝/2) both numerator and denominator

        tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2}  }{2sin(\frac{315}{2} cos(\frac{315}{2}) }

Apply formulas

 sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

  1- cos∝ =  2 sin² ∝/2

now we get

 tan (157.5) = \frac{1-cos 315}{sin315}

       

b)

          sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 330° above formula

             sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}

            sin^{2} (165) = \frac{1-cos (330) }{2}

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c )

         sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 315° above formula

             sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}

            sin^{2} (157.5) = \frac{1-cos (315) }{2}

           

d)

     cos∝  = 1- 2 sin² ∝/2

   put      ∝ = 330°

       cos 330 = 1 - 2sin^{2} (\frac{330}{2} )

      cos 330° = 1- 2 sin² (165°)

3 0
3 years ago
Directions: Place the LETTER of each value in its location in the real number system below.
finlep [7]

The most restrict classification of the numbers are given as follows:

  • Natural: 23.
  • Whole: 0.
  • Integer: -15/5 = -3, -1 and -sqrt(49) = -7.
  • Rational: 2.123, 3 and 1/4, 0.4 bar(F), square root of 16/25.
  • Irrational: π, -sqrt(35).

<h3>Which numbers are natural?</h3>

Natural numbers are positive numbers that do not have a decimal part. Hence among those, the natural numbers is: 23.

<h3>Which numbers are whole?</h3>

Whole numbers are non-negative numbers that do not have a decimal part. Hence among those, the whole number is: 0.

<h3>Which numbers are integers?</h3>

Integers are positive or negative numbers that do not have a decimal part, hence, for this problem, the integer numbers are: -15/5 = -3, -1 and -sqrt(49) = -7.

<h3>Which numbers are rational?</h3>

Fractions and terminating decimal numbers are rational, hence:

2.123, 3 and 1/4, 0.4 bar(F), square root of 16/25.

<h3>Which numbers are irrational?</h3>

Non-terminating and non-repeating decimals, such as non-exact square roots.

Hence the irrational numbers are:

π, -sqrt(35).

More can be learned about classification of numbers at brainly.com/question/13325494

#SPJ1

6 0
2 years ago
Which statement is true about the discontinuation of the function F(x)? F(x)=x+1/6x^2-7x-3
Anna35 [415]
The answer to your question is:
<span>there are holes at x= 3/2 and x=-1/3</span>
8 0
4 years ago
The ratio of red sweets to sweets that are not red is 2:3
andreyandreev [35.5K]

Answer:

Extremely sorry if my answer is wrong or doesn't make sense! Also sorry that I couldn't solve it farther, I solved it using sense and haven't made it this far in math!

Step-by-step explanation:

If red is 2:3 then that means red to green is either 2:2 or 2:1. Same goes with blue.

If green is 6:19 then we can figure out the 2 possibilities for red to green.

First Possibility:

If the red to green ratio is 2:2, then the red to green to blue is 6:6:13 because 6 + 19 - 12 = 13.

Second Possibility:

If the red to green ratio is 2:3, then the red to green to blue ratio is 4:6:15 because 6 + 19 - 10 = 15.

3 0
2 years ago
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