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mina [271]
3 years ago
14

How many single covalent bonds must a phosphorus atom form to have a complete octet in its valence shell? how many single covale

nt bonds must a phosphorus atom form to have a complete octet in its valence shell? 3 1 4 0 2?
Chemistry
2 answers:
charle [14.2K]3 years ago
4 0
Phosphorus   atom require to  form    3  single  covalent  bond  to  have  a  complete  octet  in  its  valence  shell.   Phosphorus  has  a  electron  configuration  2.8.5  hence  require  to  gain  three electrons  to  acquire  the octet  electron  configuration that  is an  electron  configuration  of  2.8.8.
Sonja [21]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Atomic number of phosphorous is 15 and its electronic configuration is [Ne]3s^{2}3p^{3}.

As there are 3 valence electrons in a single phosphorous atom. Therefore, to attain stability it will readily lose three electrons and thus forms a P^{3+} charge.

For example, in PCl_{3} there will be sharing of electrons between the phosphorous and chlorine atom.

Hence, a phosphorous atom can share its three valence electrons and thus forms three covalent bonds to have a complete octet in its valence shell.

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If a sample of hydrochloric acid is neutralized with sodium hydroxide, what products are formed?
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A rock has 12.5 percent of its original amount of potassium-40 remaining in it; potassium-40 has a half-life of 1.25 billion yea
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3 years ago
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What is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 gram
oksano4ka [1.4K]

V₂O is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 grams of the oxide.

The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

Given

Vanadium weighs 20.38 g.

The oxide's mass is 23.58 g.

% Vanadium composition: (20.38 g/23.58 g) 100%

= 86.43%

Oxygen mass equals 23.58 g minus 20.38 g

= 3.2 g

100% of oxygen's composition is (3.2/g/23.58 g)

= 13.57%

Atomic mass and number are related by composition percentage.

Vanadium's atomic weight is 50.94 g/mol.

Atomic weight of V = 86.43 / 50.94

= 1.6967

Oxygen has an atomic mass of 16 g/mol.

O atom count is 13.57/16.

= 0.8481

Now on calculation the ratio of Vanadium to the oxygen is

1.6967/0.8481 = 2/1

Ratio of whole numbers is 2:1

Thus V₂O is the empirical formula .

Learn more about empirical formula here brainly.com/question/13058832

#SPJ4

6 0
1 year ago
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