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mina [271]
3 years ago
14

How many single covalent bonds must a phosphorus atom form to have a complete octet in its valence shell? how many single covale

nt bonds must a phosphorus atom form to have a complete octet in its valence shell? 3 1 4 0 2?
Chemistry
2 answers:
charle [14.2K]3 years ago
4 0
Phosphorus   atom require to  form    3  single  covalent  bond  to  have  a  complete  octet  in  its  valence  shell.   Phosphorus  has  a  electron  configuration  2.8.5  hence  require  to  gain  three electrons  to  acquire  the octet  electron  configuration that  is an  electron  configuration  of  2.8.8.
Sonja [21]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Atomic number of phosphorous is 15 and its electronic configuration is [Ne]3s^{2}3p^{3}.

As there are 3 valence electrons in a single phosphorous atom. Therefore, to attain stability it will readily lose three electrons and thus forms a P^{3+} charge.

For example, in PCl_{3} there will be sharing of electrons between the phosphorous and chlorine atom.

Hence, a phosphorous atom can share its three valence electrons and thus forms three covalent bonds to have a complete octet in its valence shell.

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Ice cream is made by freezing a liquid mixture that, as a first approximation, can be considered a solution of sucrose (C12H22O1
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Hi.

The temperature is approximately zero degrees (0°C)

Explanation:

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Write the concentration equilibrium constant expression for this reaction.
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In a chemical reaction, the equilibrium constant refers to the value of its reaction quotient at chemical equilibrium, that is, a condition attained by a dynamic chemical system after adequate time has passed, and at which its composition has no measurable capacity to undergo any kind of further modification.  

The given reaction is: HCN (aq) + OH⁻ = CN⁻ (aq) + H2O (l)

The equilibrium constant = product of concentration of products / product of concentration of reactants

(Here, H2O is not considered as its concentration is very high)

So, Keq = [CN⁻] / [HCN] [OH⁻]


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