Answer:
it contains 2.56 x 10^15.
Explanation:
given no. of moles = 4.26 x 10^-9 atoms
one mole has 6.022 x 10^23 atoms
so it contains 4.26 x 10^-9 x 6.022 x 10^23 atoms
(If we suppose silver's atomic weight as 108.)
The main information we have to use here is the density of gold. From literature, the density of gold at room temperature is 19.32 g/cm³. To determine the mass, let's calculate the volume first. A wire is in the shape of a cylinder. Thus, the volume would be
V = πd²h/4
V = π(0.175 cm)²(1×10⁵ cm)/4
V = 2,405.28 cm³
Density = mass/volume
19.32 g/cm³ = Mass/2,405.28 cm³
Mass = 46,470 g gold wire
We have to convert 0.18 km into feet
First, we need to know the conversions:
1 inch = 2.54 cm (exact)
1 pound = 454 g
1 Liter = 1.0b quarts
1 feet = 12 inches
1 galion = 4 quarts
1 pound = 16 ounces
0.18 km x (1 feet/12 inches) x (1 inch/2.54cm) x (1000 m/1 km) x (100 cm/1 m) = 590 ft
Answer: 590 ft (2 significant figures)
39 J
P=Fd/t i belive is the answer