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mina [271]
3 years ago
14

How many single covalent bonds must a phosphorus atom form to have a complete octet in its valence shell? how many single covale

nt bonds must a phosphorus atom form to have a complete octet in its valence shell? 3 1 4 0 2?
Chemistry
2 answers:
charle [14.2K]3 years ago
4 0
Phosphorus   atom require to  form    3  single  covalent  bond  to  have  a  complete  octet  in  its  valence  shell.   Phosphorus  has  a  electron  configuration  2.8.5  hence  require  to  gain  three electrons  to  acquire  the octet  electron  configuration that  is an  electron  configuration  of  2.8.8.
Sonja [21]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Atomic number of phosphorous is 15 and its electronic configuration is [Ne]3s^{2}3p^{3}.

As there are 3 valence electrons in a single phosphorous atom. Therefore, to attain stability it will readily lose three electrons and thus forms a P^{3+} charge.

For example, in PCl_{3} there will be sharing of electrons between the phosphorous and chlorine atom.

Hence, a phosphorous atom can share its three valence electrons and thus forms three covalent bonds to have a complete octet in its valence shell.

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 <u><em>calculation</em></u>

Step 1:  find the moles of isopently acetate( C₇H₁₄O₂)

moles  =  mass÷  molar mass

From periodic table the molar mass of C₇H₁₄O₂

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moles = 1 x10⁻⁶ g÷ 130 g/mol =  7  x 10⁻⁹ moles

step 2 ; use the Avogadro's  law  constant to calculate the number of molecules

That  is according to Avogadro's law  1 mole  = 6.02 x 10²³  molecules

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<em>by cross multiplication</em>

= { (7 x 10⁻⁹ moles x  6.02 x10²³  molecules) / 1  mole} = 4.63 x 10¹⁵  molecules

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3 years ago
What is the recommended way of preparing 100ml of 0.02 from 2M NaOH in the laboratory?
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Answer:

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