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Sauron [17]
4 years ago
11

Marina is creating a flow chart of the mechanics of mantle convection and how it relates to tectonic plate movement.

Chemistry
2 answers:
Svetradugi [14.3K]4 years ago
5 0

Answer:

answer is A.

Explanation:

your welcone

mamaluj [8]4 years ago
3 0

The correct word sequence in the given flow chart will be

A.) asthenosphere, ridge push, subduct

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ELETE
yKpoI14uk [10]

Answer:

5 L

Explanation:

Use Charles law and rearrange formula

Change C to K

- Hope that helped! Please let me know if you need further explanation.

6 0
4 years ago
Why does hot water freeze faster than cold water?
weeeeeb [17]
<h2>Answer:</h2>

<u>Temperature dependency is responsible for the process that hot water freeze faster than cold water.</u>

<h2>Explanation:</h2>

The effect given above is called Mpemba Effect. According to this idea hot water freezes more quickly as compared to cold water. But until now there is no convincing explanation for this strange phenomenon.  One idea is that hot containers make better thermal contact with a refrigerator and so conduct heat more efficiently because a good conductor is good fro the transfer of heat. Another idea about this effect is that warm water evaporates more quickly and since this is an endothermic process, it cools the water making it freeze more quickly.

7 0
3 years ago
Read 2 more answers
What is the medical term for ringing, buzzing, or hissing in the ears?
Thepotemich [5.8K]
Tinnitus is the ringing in ears or buzzing and hissing
7 0
3 years ago
The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentrat
Valentin [98]

Answer:

(a)

0.0342M

(b)

t_{1/2}=17.36s\\t_{1/2}=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

\frac{1}{[NOBr]}=kt +\frac{1}{[NOBr]_0}\\\frac{1}{[NOBr]}=\frac{0.8}{M*s}*22s+\frac{1}{0.086M}=\frac{29.3}{M}\\

[NOBr]=\frac{1}{29.2/M}=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_{1/2}=\frac{1}{k[NOBr]_0}

Therefore, for the given initial concentrations one obtains:

t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.072M}=17.36s\\t_{1/2}=\frac{1}{\frac{0.80}{M*s}*0.054M}=23.15s

Best regards.

8 0
3 years ago
Read 2 more answers
HURRY PLEASE
icang [17]

The answer is b_______________\\\

6 0
3 years ago
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