X+2> _ 5, x >_5-2, x>_3
-x-2>_5, x<_ -2-5, x<_-7
the last is the answer
Answer:
27 degrees
Step-by-step explanation:
We are given that Angle AEF is 63. We can also see that EAF is a right angle. Since angles in a triangle add up to 180, we can use this to solve for AFE:
Angle AEF + EAF + AFE = 180
63 + 90 + AFE = 180
153 + AFE = 180
AFE = 27
<em>Or we can solve it another way</em>
Since EAF is a right angle, the other angles are complementary (they add up to 90) so...
Angle AEF + AFE = 90
63 + AFE = 90
AFE = 27
Answer:
g(10) = -37
Step-by-step explanation:
g(x)= -4x+3
g(1) means evaluate when x=10
g(10) = -4*10 +3
g(10) = -4*10 +3
g(10) = -40+3
g(10) = -37
Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
y = 5x + 4
Step-by-step explanation:
y - 4 = 5(x - 0)
That is point-slope form. I'm not sure if you want it in slope intercept form, but slope intercept form of the equation is -
y = 5x + 4
