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a_sh-v [17]
3 years ago
8

Using the graph, what does f(8) equal? PLEASE I NEED SO MUCH HELP!!

Mathematics
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

Step-by-step explanation:

The question is not terrifically worded. What it means is "What is the y value when x = 8" That's what f(8) conveys to you.

The answer (though zero is not marked and should be) is 1 unit above 0.

The answer is f(8) = 1 He's heading back.

You might be interested in
A rectangular prism and a square pyramid were joined to form a composite figure.
azamat

Answer:

B. 333 in.2

Step-by-step explanation:

The area of the base is 81^2

lateral is 45 x 4 = 180^2  (9x5x4)

180^2 add the 72 pyramid = 252^2 + base of 81^2 = 333^2

Composite figueres i do like this as shown to you a few seconds ago.

The triangle shows us just the height

4 inches

We can see that height is smaller central isosceles height across the center base point.

We also can remember to use the length 9inches but divide by 2 and get each triangle area this way.

4 x 1/2 base = 4x 1/2 4.5 = 4 x 2.25 = 9^2 each right side triangle

9 x 8 = 72^2

we add the areas 72+ 81+lateral 180 = 333 inches^2

8 0
3 years ago
Consider the region bounded by the curves y=|x^2+x-12|,x=-5,and x=5 and the x-axis
Tasya [4]
Ooh, fun

what I would do is to make it a piecewise function where the absolute value becomse 0

because if you graphed y=x^2+x-12, some part of the garph would be under the line
with y=|x^2+x-12|, that part under the line is flipped up

so we need to find that flipping point which is at y=0
solve x^2+x-12=0
(x-3)(x+4)=0
at x=-4 and x=3 are the flipping points

we have 2 functions, the regular and flipped one
the regular, we will call f(x), it is f(x)=x^2+x-12
the flipped one, we call g(x), it is g(x)=-(x^2+x-12) or -x^2-x+12
so we do the integeral of f(x) from x=5 to x=-4, plus the integral of g(x) from x=-4 to x=3, plus the integral of f(x) from x=3 to x=5


A.
\int\limits^{-5}_{-4} {x^2+x-12} \, dx + \int\limits^{-4}_3 {-x^2-x+12} \, dx + \int\limits^3_5 {x^2+x-12} \, dx

B.
sepearte the integrals
\int\limits^{-5}_{-4} {x^2+x-12} \, dx = [\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-5}_{-4}=(\frac{-125}{3}+\frac{25}{2}+60)-(\frac{64}{3}+8+48)=\frac{23}{6}

next one
\int\limits^{-4}_3 {-x^2-x+12} \, dx=-1[\frac{x^3}{3}+\frac{x^2}{2}-12x]^{-4}_{3}=-1((-64/3)+8+48)-(9+(9/2)-36))=\frac{343}{6}

the last one you can do yourself, it is \frac{50}{3}
the sum is \frac{23}{6}+\frac{343}{6}+\frac{50}{3}=\frac{233}{3}


so the area under the curve is \frac{233}{3}
6 0
3 years ago
dog brought a new jet ski for $299 down in 14 monthly payments are $57 how much did Doug pay for the jet ski total
Effectus [21]

If he paid $57 monthly for 14 months, the total amount paid is:

57\times14=798

He paid $798 in total

8 0
1 year ago
Simplify 4n 5 + 3.5n 5 + (-2.1n 5).
lyudmila [28]
4n 5 + 3.5n 5 - 2.1n 5 = n 5 (4 + 3.5 - 2.1) = n 5 * 5.4 = 5.4n 5
3 0
3 years ago
Read 2 more answers
(7.58•105)+(2.871•106)
Svet_ta [14]
1,100.226 is your answer :)

8 0
3 years ago
Read 2 more answers
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