It would be x is greater then 3 so anything above 3 which would be 5
So the answer is
(4) 5
Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

Answer:

Step-by-step explanation:
Given




Express the given point P as a unit tangent vector:

Next, find the gradient of P and T using: 
Where

So: the gradient becomes:

![\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]](https://tex.z-dn.net/?f=%5Ctriangle%20T%20%3D%20%5B%28sin%20%5Csqrt%203%29i%20%2B%20%28cos%20%5Csqrt%203%29j%5D%20%2A%20%20%5B%5Cfrac%7B%5Csqrt%203%7D%7B2%7Di%20-%20%5Cfrac%7B1%7D%7B2%7Dj%5D)
By vector multiplication, we have:




Hence, the rate is:
Answer:
No, it is not.
Step-by-step explanation:
comparing the two given values, 1.75 and 6, estimating 1.75 for 6 is not reasonable. This is due to the fact that converting 1.75 to the nearest whole number gives 2 which is far away from 6. Since,
6 - 2 = 4
So, estimating 1.75 for 6 would involve a large value of error. Which make it unreasonable. It would have been more reasonable to estimate 1.75 for 2.
Here’s a picture of my work. The answer is b. Hope this helps :-)
Answer:
f(t) = 5×0.87^t
Step-by-step explanation:
The general form for an exponential function described in this fashion is ...
... f(t) = (starting value) × (1 + (percent change))^t
Here, the "percent change" is -13%, or -0.13.
Then the value (1 + percent change) is (1 + (-0.13)) = 0.87. Putting this and the starting value into the form above, we have ...
... f(t) = 5 × 0.87^t