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STALIN [3.7K]
3 years ago
9

What is the lateral surface area of this rectangular prism in square centimeters

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0

Answer:

give me sec waitttttttt give me sec is their any answer choice

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What is the fraction of 12 feet of rope cut into 1/3 pieces?
Fiesta28 [93]

Answer:

1/4 hopefully this helps you with work

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3 years ago
PLEASE HELP IVE BEEN WAITING FOR 3 HOURS AND NO ANSWER
aleksandrvk [35]
This situation is governed by a linear equation:

Total Pay = Base Salary + Commissions, and here that equation is:

Total Pay = $150 + 0.14(Total of sales for the week).

Here, Total Pay = $150 + 0.14($6050) = $150 + $847 = $997
5 0
3 years ago
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PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!
Svetach [21]

h(x)=20e^{kx}

a. If h(1)=20, then 20=20e^k\implies e^k=1\implies k=0.

b. If h(1)=40, then 40=20e^k\implies e^k=2\implies k=\ln2, so that 2k+1=2\ln2+1.

c. If h(1)=10, then 10=20e^k\implies e^k=\dfrac12\implies k=-\ln2, so that k-3=-\ln2-3.

3 0
3 years ago
An employee earns $175 for 15 hours work.<br> Find the constant of variation.
LiRa [457]

Answer:

11.67

Step-by-step explanation:

Given: Employee earn $175 for 15 hours

We know, the constant of variation means the rate of change.

To know The constant of variation, we need to find how much employee earn each hour.

∴ Constant of variation= \frac{Total\ earning}{Total\ working\ hours}

Constant of variation= \frac{175}{15}= 11.666

∴ Constant of variation= 11.67. (rounding off)

8 0
3 years ago
Find the equation of a line that runs through
MAVERICK [17]

Answer:

The equation of a line that runs through  (-6,2) and is parallel to a line with a slope of (-1/4)     is  x + 4y  - 2 = 0

Step-by-step explanation:

Slope of the parallel  equation is m 1 = (-1/4)

<em>If the two liner are parallel the, slope of both lines are equal.</em>

⇒The slope of the equation of line = m2  = m1  = -(1/4)

The point (x0, y0)  = (-6,2)

Now, by THE POINT SLOPE FORMULA:  The equation of a line is given as

( y - y0)  =  m (x -x0)

Now, here the equation of line is given as:

y - 2 = (\frac{-1}{4}) (x - (-6))   \implies  4(y-2) = -1(x + 6)

or, 4y - 8 + x + 6 = 0

or, x + 4y  - 2 = 0

Hence, the required line equation is  x + 4y  - 2 = 0

7 0
3 years ago
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