Answer:
a^2 - 3
Step-by-step explanation:
(3a^2 + 1) - (4 + 2a^2)
3a^2 + 1 - 4 - 2a^2
a^2 - 3
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
Answer:
x=16; y=24
Step-by-step explanation:
for (x,23), 23=0.5x+15
x=16
for (18xy), y=0.5*18+15=24
<span>{(1, 2), (3, 2), (5, 7)} is a function
</span>
Answer:
b. They can both be 90 degree angles
c. Acute angles are by definition 90 degrees, and acute is less than but not equal to 90 degrees
d. should be always
e. should be never (explanation: they have to be adjacent to be supplementary, and vertical angles are never adjacent)
Step-by-step explanation:
