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EleoNora [17]
3 years ago
11

3(t-3)=5(2t+1) solve the following linear equations

Mathematics
2 answers:
Feliz [49]3 years ago
4 0

Step-by-step explanation:

3(t-3)=5(2t-1)

= 3t-9=10t-5

= 3t-10t = -5+9

= -7t = 4

= -t = 4/7

= - 4/7 Answer

hope it helps

hammer [34]3 years ago
3 0
Answer 3(t-3) = 5(2t+1): t = -2
T= -2


Plz mark brainliest if it helps
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The multiplication property of equality could be used to solve which of the following equations?
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( x+2)( x-3)=0

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What is the value of the expression 5y2 + 4x when x = 2.5 and y = 3?
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You are taking a multiple-choice test that has 5 questions. Each of the questions has 3 answer choices, with one correct answer
Anna11 [10]

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4 years ago
<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"
vekshin1

{\qquad\quad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} }  = 34

[ add 2 on both sides ]

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} } + 2  = 34 + 2

[ form identity : a² + b² + 2ab ]

\qquad \sf  \dashrightarrow \:  {(x)}^{2}  +  { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2}  + 2 \sdot(x)  \sdot  \bigg(\cfrac{1}{x} \bigg)  = 36

[ a² + b² + 2ab = (a + b)² ]

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\qquad \sf  \dashrightarrow \: x  +  \cfrac{1}{x}    =   \pm 6

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

8 0
2 years ago
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