This question is incomplete, the complete question is;
A block of mass m begins at rest at the top of a ramp at elevation h with whatever PE is associated with that height. The block slides down the ramp over a distance d until it reaches the bottom of the ramp.
How much of its original total energy (in J) survives as KE when it reaches the ground? m = 9.9 kg h = 4.9 m d = 5 m μ = 0.3 θ = 36.87°
Answer:
the amount of its original total energy (in J) that survives as KE when it reaches the ground will is 358.975 J
Explanation:
Given that;
m = 9.9 kg
h = 4.9 m
d = 5 m
μ = 0.3
θ = 36.87°
Now from conservation of energy, the energy is;
Et = mgh
we substitute
Et = 9.9 × 9.8 × 4.9
= 475.398 J
Also the loss of energy i
E_loss = (umg cosθ) d
we substitute
E_loss = 0.3 × 9.9 × 9.8 × cos36.87° × 5
= 116.423 J
so the amount of its original total energy (in J) that survives as KE when it reaches the ground will be
E = Et - E_loss
E = 475.398 J - 116.423 J
E = 358.975 J
Answer:
5.096*10^-8
Explanation:
Given that
The average value of the electromagnetic wave is 310 mW/m²
To find the maximum value of the magnetic field the wave is closest to, we say
Emax = √Erms
Emax = √[(2 * 0.310 * 3*10^8 * 4π*10^-7)]
Emax = √233.7648
Emax = 15.289
Now, with our value of maximum electromagnetic wave gotten, we divide it by speed of light to get our final answer
15.289 / (3*10^8) = 5.096*10^-8 T
Suffice to say, The maximum value of the magnetic field in the wave is closest to 5.096*10^-8
The electrons in an atom can only occupy certain allowed energy levels. ... Only certain energy levels are allowed, so only certain transitions are possible and hence specific wavelengths are emitted when an electron drops to a lower energy level
Explanation:
Answer:
Ali hear the sound in 0.046 seconds.
Explanation:
Given:
Distance between Ali and Abdi = 300m
Speed of sound in steel = 6500m/s
To Find :
How much sooner does Ali hear the sound = ?
Solution:
We can find the time in which the sound made by Abdi with a stone on the rail by using the speed formula
We know that
![Speed = \frac{Distance}{time}\\](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7Btime%7D%5C%5C)
On substituting the given values,
![6500 = \frac{300}{time}\\](https://tex.z-dn.net/?f=%206500%20%3D%20%5Cfrac%7B300%7D%7Btime%7D%5C%5C)
![time = \frac{300}{6500}\\](https://tex.z-dn.net/?f=%20time%20%3D%20%5Cfrac%7B300%7D%7B6500%7D%5C%5C)
![time = \frac{300}{6500}\\](https://tex.z-dn.net/?f=%20time%20%3D%20%5Cfrac%7B300%7D%7B6500%7D%5C%5C)
Time = 0.046 seconds