Gravitational Potential Energy = weight x height
for 1 meter:
GPE = 5 x 1
= <u>5N</u>
for 1.5 metres:
GPE = 5 x 1.5
= <u>7.5N</u>
for 2 metres:
GPE = 5 x 2
= <u>10N</u>
Here we can use the concept of Height and distance
so here we know that
angle of depression at the foot of the statue is 17 degree
angle of depression at the exit gate is 14 degree
So here the distance of foot of the statue is related as
so here we will have
similarly for exit gate the distance is given as
now the distance between gate and foot of statue is given as
Answer:
5.00
Explanation:
a sinθ=mλ
You are missing (a) so you move sinθ to the other side than solve from there.
Answer:
Explanation:
We are given that
When d=3 m
We have to find the intensity when the distance from the light bulb is 2 m away.
According to question
Intensity,
Where k=Proportionality constant.
Substitute the values
Intensity when d=2 m
Answer:
As the ball gains height it's potential energy will increase and it's kinetic energy will decrease. As the ball falls back down to the ground the kinetic energy will increase and it's potential energy will decrease.