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Yakvenalex [24]
3 years ago
14

How does this app work

Physics
1 answer:
ohaa [14]3 years ago
6 0

Hello! ^^

Welcome to Brainly! Blah-blah

We are so excited, to meet you!

Brainly, is a website for you for answering questions, asking for help! if you need too. Plus, if you answer questions with explanation, you can also become a moderator in here too! But, you are not allow to answer d.umb questions on brainly... Plus, please be careful cause now there is scammers, on brainly... and they may give you a virus... So if you see a question in that don't press that link, just report...

And I hope you, will enjoy in brainly!

Have a great day!

#LearnWithBrainly

Answer:

Jace~

Plus, here is a anime image that might make your day happy. . .

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A support crossbeam on a high speed train is made from a titanium rod that has a length of 0.650m when measured by an observer o
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Answer:

A) The crossbeam is moving relative to the observer on the platform so the height appears contracted.

Explanation:

The observer on the train and the beam are in the same reference frame. That means observer on the train will measure the proper length of the beam not the contracted length . the observer is outside and the plank is in the moving system,it will appear to be moving.

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If you placed a dot on a world map to represent the location of every earthquake in the last 100 years, where would you see eart
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jenyasd209 [6]

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The box leaves position x=0x=0 with speed v0v0. The box is slowed by a constant frictional force until it comes to rest at posit
const2013 [10]

Answer:

fr = ½ m v₀²/x

Explanation:

This exercise the body must be on a ramp so that a component of the weight is counteracted by the friction force.

The best way to solve this exercise is to use the energy work theorem

            W = ΔK

Where work is defined as the product of force by distance

           W = fr x cos 180

The angle is because the friction force opposes the movement

          Δk =K_{f} –K₀

          ΔK = 0 - ½ m v₀²

We substitute

         - fr x = - ½ m v₀²      

           fr = ½ m v₀²/x

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