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Delicious77 [7]
3 years ago
5

Ali and Abdi go for a walk along an abandoned railroad truck , Ali puts one ear next to a rail, while Abdi 300m away taps in the

rail with a stone . How much sooner does Ali hear the sound (speed of sound in steel is 6500m/s).
Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

Ali hear the sound in 0.046 seconds.

Explanation:

Given:

Distance between Ali and Abdi =  300m

Speed of sound in steel = 6500m/s

To Find :

How much sooner does Ali hear the sound = ?

Solution:

We can find the time in which the sound made by Abdi with a stone on the rail by using the speed formula

We know that

Speed = \frac{Distance}{time}\\

On substituting the given values,

6500 = \frac{300}{time}\\

time = \frac{300}{6500}\\

time = \frac{300}{6500}\\

Time  = 0.046 seconds

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What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.
kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

Charge on the parallel plate capacitor, q = 5.7\ \mu C=5.7\times 10^{-6}\ C

Electric field, E = 3.1 kV/mm = 3100000 V/m

The electric field of a parallel plates capacitor is given by :

E=\dfrac{q}{A\epsilon_o}

A=\dfrac{q}{E\epsilon_o}

A=\dfrac{5.7\times 10^{-6}\ C}{3100000\ V/m\times 8.85\times 10^{-12}\ F/m}

A = 0.208 m²

So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.

8 0
3 years ago
What is the melting point of substance A?
Misha Larkins [42]

Answer:

Solids are easily recognized by their ability to retain a fixed shape and definite volume. Particles making

up a solid are held together in a rigid form. They are not free to move about or slide past one another and

the solid does not have the ability to flow. (Although the particles of a solid do not move position to position, they do have motion in that they are constantly vibrating.

To change the temperature of a solid, heat energy must be added. The amount of heat energy that changes

the temperature of 1.0 g of a solid by 1.0°C is called its specific heat (c). Each substance has its own

specific heat. The specific heat of ice is 2.1 Joules/g°C. In other words we must supply 1.0 gram of ice

with 2.1 Joules of heat energy to raise its temperature by 1.0 °C.

The general equation for calculating heat energy to change the temperature of a solid is:

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Q = m c DT

10 g 10 g 10 g 10 g 10 g 10 g

Calculate the heat necessary to change 10 g of ice(s) at -20 °C to 10 g of ice(s) at 0°C. (A-B)

Q = mc∆T = (10 g) (2.1 J/g°C) (20°C) = 420 J

If you continue to add heat energy once the temperature of the ice reaches 0°C , the heat absorbed is called

the heat of fusion (Lf). This heat is used to cause a change of phase (from a solid to a liquid). This heat is

increasing the potential energy of the molecules of the solid. No temperature change takes place. Each

substance has its own heat of fusion. The heat of fusion for ice is 340 Joules/g. Exactly the same amount

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Calculate the heat necessary to change 10 g of ice(s) at 0°C to 10 g of water(l) at 0°C.(B-C)

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Q = mLf = (10 g)( 340 J/g) = 3400 J

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