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m_a_m_a [10]
3 years ago
12

What is mean by gravitational force​

Physics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

Answer:

<u>Gravitational Force</u> is a force that attracks two objects with mass. For example, you are being pulled onto this planet, and that's why when you jump upwards, you fall back down quickly. A fun fact is that every object, even the entire universe, are pulling all on each other, including you!

#learnwithbrainly

Learn More:

brainly.com/question/8990206

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How is an electromagnet different from a bar magnet?
Umnica [9.8K]

Answer:

The answer should be C

Explanation:

The reason for that is because electromagnet needs electricity to start attracting anything at all but it's attracting power is also stronger because of it

Warning: This may or may not be a completely correct answer, hope you compare answer and don't blindly trust my answer

6 0
3 years ago
Read 2 more answers
A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va
ohaa [14]

Answer:

d' = d /2

Explanation:

Given that

Distance = d

Voltage =V

We know that energy in capacitor given as

U=\dfrac{1}{2}CV^2

C=\dfrac{\varepsilon _oA}{d}

U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2

If energy become double U' = 2 U then d'

U'=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2\times \dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2

2 d ' = d

d' = d /2

So the distance between plates will be half on initial distance.

7 0
3 years ago
Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope
Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J   the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

       

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

  = -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

                     = 26,754 (0.816)

                     = 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c.  What is the work done by the gravitational force on the sled?

By using  the formula:

Gravity work = mgdsinθ

                    = 97.5 kg * 9.8 m/s² * 28 m * sin 60

                    = 23,170 J

23,170 J   the work, in joules done by the gravitational force on the sled .

       

D. What is the total work done?

By adding all the values

work done =  -1337.3 + 21,835 + 23,170

                 = 43,670 J

The net work done on the sled, in joules is 43,670 J.

Learn more about friction work here:

brainly.com/question/14619763

#SPJ1

4 0
2 years ago
Question 7 of 20
slamgirl [31]

Answer:

high number of coils in the wire

5 0
3 years ago
5. In the image below, the focus lines are shown. What can be done to bring the apple into focus?
Vitek1552 [10]

In the image below, the focus lines are shown. The step can be done to bring the apple into focus is make the lens rounder. The correct option is A.

<h3>What is lens?</h3>

The lens is in spherical shape may be diverging or converging.

As light enters the eye, it is focused on the retina. Changing the pupil diameter, regulates the amount of light entering the eye. Changing lens shape will focus the light.

The changes in lens shape needed to maintain focus as the object distance changes.

Thus, the correct option is A.

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brainly.com/question/17014859

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3 0
2 years ago
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