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soldi70 [24.7K]
3 years ago
10

A sample of gas at a fixed pressure has a temperature of 300 K and a volume of 3 L. Calculate the volume if the gas is heated to

700 K.
Chemistry
1 answer:
Komok [63]3 years ago
3 0

Answer:300k=3L

             700k=x

cross multiply

300x=2100; x=7L

Explanation:

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How do the chemical characteristics of carbon affect the characteristics of organic molecules?
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4 0
3 years ago
Calculate ΔH for the reaction: C(graphite) + 2H 2(g) + 1/2 O 2(g) => CH 3OH(l) Using the following information: C(graphite) +
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Answer:

\Delta H for the given reaction is -238.7 kJ

Explanation:

The given reaction can be written as summation of three elementary steps such as:

C(graphite)+O_{2}(g)\rightarrow CO_{2}(g) \Delta H_{1}= -393.5 kJ

2H_{2}(g)+O_{2}(g)\rightarrow 2H_{2}O(l) \Delta H_{2}= (2\times -285.8)kJ

CO_{2}(g)+2H_{2}O(l)\rightarrow CH_{3}OH(l)+\frac{3}{2}O_{2}(g)  \Delta H_{3}= 726.4 kJ

---------------------------------------------------------------------------------------------------

C(graphite)+2H_{2}(g)+\frac{1}{2}O_{2}(g)\rightarrow CH_{3}OH(l)

\Delta H=\Delta H_{1}+\Delta H_{2}+\Delta H_{3}=-238.7 kJ

4 0
3 years ago
How much pv work is done in kilojoules for the reaction of 0.68 mol of h2 with 0.34 mol of o2 at atmospheric pressure if the vol
dsp73
The delta H of -484 kJ is the heat given off when 2 moles of H2 react with 1 mole of O2 to make 2 moles of H2O. You don't have anywhere near that much reactants, only 1/4 as much

<span>actual delta H = 0.34  moles H2 x (-484 kJ / 2 moles H2) = 823 kJ </span>

<span>delta E = delta H - PdeltaV = 823 kJ - 0.41 kJ = 822 kJ</span>
3 0
3 years ago
A patient gets 2.1 L of fluid over 19 hours through an IV. The drop factor is 20 gtt/mL.Calculate the drip rate in drops per min
Aleks [24]
<span>The rate of infusion is 2.1L/19h or 2100mL/19h (as 1L = 100 mL).
       
To convert 19 hours to minutes we multiply as follows:
   
19 hours = (19 hours) x (60 minutes/1 hour) = 1140 minutes
       
So the rate of infusion becomes:
   
2100mL /1140 min
       
In order to converted mL to drops (gtt) we multiply the rate of infusion with the drop factor to get the drip rate:
       
(2100mL/1140min) x (20 gtt/mL) = 36.8 gtt/min</span>
8 0
3 years ago
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