Answer:
Because boys are overrated
Explanation:
Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
Answer:
2,3,6,1
2,3,6,1
Explanation:
The unbalanced reaction expression is given as:
AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.
aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃
Conserving Al; a = 2d
Br: 3a = c
K: 2b = c
S: b = 3d
O: 4b = 12d
Let a = 1, c = 3, d =
b =
Multiply through by 2 to give;
a = 2, b = 3, c = 6 and d = 1
2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃
Answer:
ok.. what is your question??? confused
D:
When electrons are gained, the charge of the atom decreases.
When you are given an atom with a charge, the oxidation of that atom is the charge. So by going from a Cr^3+ (Oxidation Number = 3) to a Cr^2+ (Oxidation Number = 2), the Oxidation Number thus decreases.