Answer:
The volumetric ratio is 0,71
Explanation:
Let's begin with the equation:
(1)
Where:
Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume
And we know:
(2)
Where:
Vg: Gasoline Volume and Vk: Kerosene Volume
Therefore replacing (2) into (1):

(3)
Where:
Dg: Gasoline Density and Dk: Kerosene Density
The specific gravity is defined as:

Therefore:

Where:
Dref: Reference Density
SGb: Blend Specific Gravity
SGg: Gasoline Specific Gravity (which is 0.7 approximately)
SGk: Kerosene Specific Gravity
Replacing these equations into (3) we get:





Replacing with the Specific Gravity data, we obtain:





Networks of feeding relationships is correct
The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2