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grandymaker [24]
2 years ago
6

List three conditions for separating crude oil constituents pls someone help me out ​

Chemistry
1 answer:
Alborosie2 years ago
4 0

Answer:

All refineries have three basic steps: separation, conversion and treatment. During the separation process, the liquids and vapors separate into petroleum components called factions based on their weight and boiling point in distillation units.

Explanation:

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A compound X has the following percentage composition 66.7% carbon, 11.1% hydrogen and 22.2% oxygen .Calculate the empirical for
Digiron [165]

Explanation:

c. h. o

66.7%. 11.1%. 22.2%

____. ____. ____

12. 1. 16

1.558. 11.1. 1.39. (divide by the smallest)

1. 8. 1

empirical formula=ch8o

4 0
2 years ago
2H2S + 3O2 → 2SO2 + 2H2O<br><br><br>1. For every 10.0 g of H2S how many moles of SO2 are formed?
Veseljchak [2.6K]

Answer:10

Explanation:

7 0
2 years ago
Does a large or small body cool faster?
Nataly [62]

Answer:

SO… The larger wire looses heat energy faster, however the smaller wire decreases temperature faster. ... Their surface area is much larger in proportion to their body mass and they lose heat through their skin when it is cold and they gain heat through their skin when it is hot much faster than an adult does.

Explanation:

8 0
2 years ago
How many grams of NH3 can be produced from 2.51 mil of N2 and excess H2 ?
salantis [7]

Answer:

85.34g of NH3

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

N2 + 3H2 —> 2NH3

Step 2:

Determination of the number of moles of NH3 produced by the reaction of 2.51 moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 2.51 moles of N2 will react to produce = (2.51 x 2)/1 = 5.02 moles of NH3.

Therefore, 5.02 moles of NH3 is produced from the reaction.

Step 3:

Conversion of 5.02 moles of NH3 to grams. This is illustrated below:

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Number of mole of NH3 = 5.02 moles

Mass of NH3 =..?

Mass = mole x molar Mass

Mass of NH3 = 5.02 x 17

Mass of NH3 = 85.34g

Therefore, 85.34g of NH3 is produced.

3 0
2 years ago
A 25.0 ml sample of 0.150 m benzoic acid is titrated with a 0.150 m naoh solution. what is the ph at the equivalence point? the
Ad libitum [116K]

Solution:

At the equivalence point, moles NaOH = moles benzoic acid  

HA + NaOH ==> NaA + H2O where HA is benzoic acid  

At the equivalence point, all the benzoic acid ==> sodium benzoate  

A^- + H2O ==> HA + OH- (again, A^- is the benzoate anion and HA is the weak acid benzoic acid)  

Kb for benzoate = 1x10^-14/4.5x10^-4 = 2.22x10^-11  

Kb = 2.22x10^-11 = [HA][OH-][A^-] = (x)(x)/0.150  

x^2 = 3.33x10^-12  

x = 1.8x10^-6 = [OH-]  

pOH = -log [OH-] = 5.74  

pH = 14 - pOH = 8.26  


5 0
2 years ago
Read 2 more answers
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