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klasskru [66]
3 years ago
9

In a chemical reaction 88g of CO2 was produced at r.t.p. Calculate the volume of CO2 in dm??

Chemistry
1 answer:
Tems11 [23]3 years ago
6 0

Explanation:

RFM = 44 \: g \\ 44g \: contain \: 1 \: mole \\ 88g \: will \: contain \: ( \frac{88}{44}  \times 1) \\  = 2 \: moles \\ at \: room \: temperature \\ 1 \: mole \: occupies \: 24 \:  {dm}^{3}  \\ 2 \: moles \: occupies \: (2 \times 24) \\  = 48 \:  {dm}^{3}

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water and ammonia are polar. The hydrogen atoms in each have a slight positive charge. What does that tell you about the oxygen
Andreas93 [3]

Answer:

More electronegative

Explanation:

The oxygen and nitrogen in ammonia shows that they are more electronegative than the hydrogen  atoms.

  • Electronegativity shows the affinity of an atom for valence electrons.
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The oxygen atom in water and the nitrogen atom in ammonia are more electronegative.

They attract the electrons more and they then become negatively charged.

The hydrogen will then become positively charged in the shared covalency.

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3 years ago
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Answer:

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8 0
3 years ago
What is a unicellular organism?
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3 0
3 years ago
Read 2 more answers
Part A Which of the following statements about chemical formulas is FALSE? Which of the following statements about chemical form
statuscvo [17]

Answer: Option (a) is the correct answer.

Explanation:

Subscript present in chemical formula of a compound represents the number of atoms of the element actually present in it.  

For example, in C_{7}H_{7}NO_{2} the subscripts present in it are 7, 7, 1, and 2.

A subscript is not responsible for determining the relative mass of each type of an atom because a subscript simply represents the number of atoms of each type of an element participating or combining with other atoms of a compound.

Thus, we can conclude that the statement subscripts represent the relative mass of each type of atom in the compound, is false.

8 0
4 years ago
What is the half-life of an isotope that decays to 12.5% of its original activity in 19.8 hours?
katen-ka-za [31]
x= x_{0}  e^{kt} ,where~ x ~is~ the ~ |amount\ of \material\ at\ any~~time~t

and~ x_{0} ~the~original~amount.
when~x=  \frac{12.5}{100} x_{0}  }= \frac{125}{1000}  x_{0}
\frac{x}{ x_{0} } = \frac{125}{1000}= \frac{1}{8}
when t=19.8 hrs,
x= x_{0}  e^{19.8 k}, 
 \frac{x}{ x_{0} } = e^{19.8 k}, 
 \frac{1}{8} = e^{19.8k} ,
ln \frac{1}{8} =19.8 k,

ln1-ln8=19.8k,
0-ln 2^{3} =19.8 k,
-3 ln2=19.8k
k= \frac{-3 ln2}{19.8} = \frac{- ln 2}{6.6}x= x_{0}  e^{ \frac{-ln2}{6.6}t } ,
 \frac{x}{ x_{0} } = e^{ \frac{- ln 2}{6.6}t } 
\frac{1}{2} = e^{ \frac{- ln2}{6.6}t } = \frac{1}{ e^{ \frac{ln 2}{6.6} t} } ,
2= e^{ \frac{ln2}{6.6}t } ,
ln2=ln  e^{ \frac{ln 2}{6.6}t } = \frac{ln 2}{6.6} t~ln e= \frac{ln2}{6.6} t,
8 0
4 years ago
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