Answer:
The energy associated with motion ends up as kinetic energy . The energy associated with position ends up as potential energy .
Explanation:
The answer is ii) the liquid called tea.
That is ii) the liquid called tea is a mixture.
the liquid called tea is a homogeneous mixture that contains organic and inorganic compounds, sugar(organic carbohydrate),tea leaf extract(organic), water(inorganic).
Whereas (iii) distilled water, is a pure substance while (I) gello is a colloid.
The world's oceans are crucial to heating the planet.
hope this helps!! :D
<h3>
Answer:</h3>
8.4 × 10²³ atoms H₃PO₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 1.4 moles H₃PO₄
[Solve] atoms H₃PO₄
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
8.4308 × 10²³ atoms H₃PO₄ ≈ 8.4 × 10²³ atoms H₃PO₄
The molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.
<h3>How to calculate molar heat of fusion?</h3>
The heat of fusion of a substance can be calculated by using the following formula:
Q = m∆H
Where:
- Q = quantity of heat
- m = mass
- ∆H = change in temperature of fusion
However, the quantity of heat has been given as 9840calories. The molar heat of fusion of iron can be calculated by dividing the heat of fusion by the number of moles of iron.
Moles of iron = mass ÷ molar mass
moles = 200g ÷ 55.8g/mol
moles = 3.58moles
molar heat of fusion = 9840 cal ÷ 3.58mol
molar heat of fusion = 2748.6 cal/mol
Therefore, the molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.
Learn more about molar heat of fusion at: brainly.com/question/8263730