y = 3 is the line of reflection
Under a reflection in a line, corresponding points of the original and it's image should be equidistant from the line of reflection
y = 3 is the horizontal line passing through all the points with a y-coordinate of 3
A is 1 unit above and A' is 1 unit below the line
B is 3 units above and B' is 3 units below
C is 1 unit below and C' is 1 unit above
D is 1 unit below and D' is 1 unit above
The vertices of the figure and the image are all equidistant from y = 3
To solve this equation, start by noticing that you want to find t when P is 75%, or 0.75. Plug in 0.75 for P. Please see the attached screenshot for a step-by-step. The correct answer is 29.496 days.
EDIT 2: I actually was correct! You check the answer by substituting 29.496 for t in the original equation set equal to 0.75. It is 0.75. I had forgotten the negative sign when I checked.
The slope of this line is 1 and the y-intercept is -2.
In order to find this, you need to put it in slope intercept form. This is done below for you.
3x - 3y = 6 -----> Subtract 3x from both sides
-3y = -3x + 6 -----> Divide by -3
y = x - 2
Now that you have this, you can find the slope by looking for the coefficient of x. In this case it is 1. You can find the intercept as the constant at the end, which is -2.
Answer:Just a tip...If you enter that in desmos it will plot it for you!
Step-by-step explanation:
Hopefully that helps!
Answer:
A,C,D. those 3 have a percent error of less then 15%