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maxonik [38]
3 years ago
12

5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significan

t figures)
Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

P2 = 1250mmHg

Explanation:

V1 = 5.0L

P1 = 750mmHg

V2 = 3.0L

P2 = ?

According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k/V k = P*V

P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn

P1 *V1 = P2 * V2

Solve for P2

P2 = (P1 * V1) / V2

P2 = (750 * 5.0) / 3.0

P2 = 3750 / 3

P2 = 1250mmHg

The final pressure of the gas is 1250mmHg

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