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maxonik [38]
3 years ago
12

5.00 L of air at 750 mmHg pressure was compressed into a 3.00 L steel cylinder. What is the final pressure? (round to significan

t figures)
Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

P2 = 1250mmHg

Explanation:

V1 = 5.0L

P1 = 750mmHg

V2 = 3.0L

P2 = ?

According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

P = k/V k = P*V

P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn

P1 *V1 = P2 * V2

Solve for P2

P2 = (P1 * V1) / V2

P2 = (750 * 5.0) / 3.0

P2 = 3750 / 3

P2 = 1250mmHg

The final pressure of the gas is 1250mmHg

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Explanation:

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Let is assume that at equilibrium the concentrations of given species are as follows.

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     K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

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              = 11.24 \times 10^{-4}

Now, according to the concentration values at the re-established equilibrium the value for [FeSCN^{2+}] will be calculated as follows.

             K_{eq} = \frac{[Fe^{3+}][SCN^{-}]}{[FeSCN^{2+}]}

        11.24 \times 10^{-4} = \frac{8.12 \times 10^{-3} \times 7.84 \times 10^{-3}}{[FeSCN^{2+}]}

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7 0
3 years ago
Can someone help me understand what 1b is asking and how to answer it?
icang [17]
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I hope this helps.  Let me know in the comments if anything is unclear.
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Sulfuric acid, H2SO4, can be neutralized by sodium hydroxide, NaOH. The unbalanced equation is: H2SO4(aq) + NaOH(aq) → Na2SO4(aq
evablogger [386]
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ohaa [14]

Answer:

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Explanation:

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