Answer:
Oxygen is in excess.
Explanation:
The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.
The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.
If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.
Answer:
They are Weaker than a chemical
<h2>bond</h2>
corrected by the one in the comment section
Answer:
Mass of 
produced = 32 g
Explanation:
Calculation of the moles of 
as:-
Mass = 82.4 g
Molar mass of = 122.55 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the reaction shown below:-
2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas
So,
0.67237 moles of potassium chlorate on reaction forms 
moles of oxygen gas
Moles of oxygen gas = 1 mole
Molar mass of oxygen gas = 32 g/mol
<u>Mass of produced = 32 g</u>
It is a simple stoichiometry problem. We have been given with balanced equation and 5.00 moles of HCl and have to calculate the moles of H2.
<span>From the balanced equation it is being clear that 2 moles of HCl are produced by 1 mole of H2. so, 1 mole of HCl will be produced by 1/2 moles of H2. So, the mole ratio of H2 and HCl is 1:2 </span>
<span>to calculate the moles of H2 for the given moles of HCl, multiply the moles of HCl by the mole ratio of H2 and HCl. </span>
<span>5.00 mole HCl x (1 mole H2/ 2 mole HCl) </span>
<span>= 2.50 mole H2 </span>
<span>so, to produce 5.00 moles of HCl, 2.50 moles of H2 are required.</span>
