Answer: The value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Explanation:
Given: Moles of solute = 0.793 mol
Mass of solvent = 0.758
![\Delta T_{b} = 3.80^{o}C](https://tex.z-dn.net/?f=%5CDelta%20T_%7Bb%7D%20%3D%203.80%5E%7Bo%7DC)
As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.
![Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m](https://tex.z-dn.net/?f=Molality%20%3D%20%5Cfrac%7Bno.%20of%20moles%7D%7Bmass%20of%20solvent%20%28in%20kg%29%7D%5C%5C%3D%20%5Cfrac%7B0.793%20mol%7D%7B0.758%20kg%7D%5C%5C%3D%201.05%20m)
Now, the values of
is calculated as follows.
![\Delta T_{b} = i\times K_{b} \times m](https://tex.z-dn.net/?f=%5CDelta%20T_%7Bb%7D%20%3D%20i%5Ctimes%20K_%7Bb%7D%20%5Ctimes%20m)
where,
i = Van't Hoff factor = 1 (for chloroform)
m = molality
= molal boiling point elevation constant
Substitute the values into above formula as follows.
![\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m](https://tex.z-dn.net/?f=%5CDelta%20T_%7Bb%7D%20%3D%20i%5Ctimes%20K_%7Bb%7D%20%5Ctimes%20m%5C%5C3.80%5E%7Bo%7DC%20%3D%201%20%5Ctimes%20K_%7Bb%7D%20%5Ctimes%201.05%20m%5C%5CK_%7Bb%7D%20%3D%203.62%5E%7Bo%7DC%2Fm)
Thus, we can conclude that the value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Answer:
A = Metallic Bond
B = Strong bonding, strong conductor, high melting and boiling points
Explanation:
Since the bond is between two metals (located in groups 11 and 12), they would experience metallic bonding. Metallically bonded molecules have high melting and boiling points due to the strength of the metallic bond. They also experience strong electrical current due to the there delocalized electrons.
Answer:
A
Explanation:
The molecule with the strongest intramolecular bond is HF. Hydrogen fluoride is the answer due to the strong and highly electronegative nature of Fluorine.
- Fluorine is the most electronegative element in nature.
- When it combines with other substances, due to its electronegative property, it draws most of the electrons closest to itself in the bond.
- This tendency and ability makes the shared electrons closer the fluorine in the bond.
- The strong polarization that ensues confers a very strong covalent bond pair on the bond formed.