Jessica jogs on a path that is 25 km long to get to a park that is south of the jogging path. If it takes Jessica 2.5 hours then
2 answers:
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Answer:
- vertical scaling by a factor of 1/3 (compression)
- reflection over the y-axis
- horizontal scaling by a factor of 3 (expansion)
- translation left 1 unit
- translation up 3 units
Step-by-step explanation:
These are the transformations of interest:
g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k
g(x) = f(x) +k . . . . vertical translation by k units (upward)
g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis
g(x) = f(x-k) . . . . . horizontal translation to the right by k units
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Here, we have ...
g(x) = 1/3f(-1/3(x+1)) +3
The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:
- vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
- reflection over the y-axis . . . 1/3f(-x)
- horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
- translation left 1 unit . . . 1/3f(-1/3(x+1))
- translation up 3 units . . . 1/3f(-1/3(x+1)) +3
_____
<em>Additional comment</em>
The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.
The horizontal transformations could also be described as ...
- translation right 1/3 unit . . . f(x -1/3)
- reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)
The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.
Given a = 3 and b = - 8 ,
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
= > 2b² - 4a + 4a²
= > 2( - 8 )² - 4( 3 ) + 4( 3 )²
= > 2( 64 ) - 4( 3 ) + 4( 9 )
= > 128 - 12 + 36
= > 116 + 36
= > 152
Answer:
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 10 - 1 = 9
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 3.25
The margin of error is:
M = T*s = 3.25*25 = 81
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 12,556 - 81 = 12,475 pounds
The upper end of the interval is the sample mean added to M. So it is 12,556 + 81 = 12,637 pounds.
The 99% confidence interval of the population mean for the weights of adult elephants is between 12,475 pounds and 12,637 pounds.